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Helen [10]
4 years ago
13

A contractor needs to buy nails to build a house. The nails come in small boxes and large boxes. Each small box has 100 nails an

d each large box has 350 nails. The contractor bought a total of 9 boxes that have 2400 nails altogether. Write a system of equations that could be used to determine the number of small boxes purchased and the number of large boxes purchased. Define the variables that you use to write the system.
Mathematics
1 answer:
ExtremeBDS [4]4 years ago
6 0

Answer:

The system 150x+400y=1950 and x = y+2 could be used to determine the number of small boxes and large boxes ordered where x represents the number of small boxes and y represent the number of large boxes.

Step-by-step explanation:

Given,

Number of nails in small box = 150 nails

Number of nails in large box = 400 nails

Total nails in ordered boxes = 1950 nails

Let,

x be the number of small boxes ordered.

y be the number of large boxes ordered.

According to given statement;

150x+400y=1950          Eqn 1

The contractor bought 2 more small boxes than large boxes

x = y+2                           Eqn 2

The system 150x+400y=1950 and x = y+2 could be used to determine the number of small boxes and large boxes ordered where x represents the number of small boxes and y represent the number of large boxes.

Step-by-step explanation:

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Determine whether the systems have one solution, no solution, or infinitely many solutions
Lerok [7]

Answer:

First system: no solution

Second system: one solution

Third system: one solution

Fourth system: infinite solutions

Fifth system: no solution

Step-by-step explanation:

First system: 3x-2y=3; 6x-4y=1

From the first equation: y = (3x - 3)/2

Using this value of y in the second equation:

6x - 6x + 6 = 1

6 = 1 -> System has no solution

Second system: 3x-5y=8; 5x-3y=2

From the first equation: x = (8 + 5y)/3

Using this value of x in the second equation:

5*(8 + 5y) - 9y = 6

40 + 25y - 9y = 6

16y = -34 -> y = -2.125

x = (8 - 5*2.125)/3 = -0.875

This system has one solution

Third system: 3x-2y=8; 4x-3y=1

 From the first equation: x = (8 + 2y)/3

Using this value of x in the second equation:

4*(8 + 2y) - 9y = 3

32 + 8y - 9y = 6

y = 26

x = (8 + 2*26)/3 = 20

This system has one solution

Fourth system: 3x-6y=3; 2x-4y=2

  From the first equation: x = 1 + 2y

Using this value of x in the second equation:

2*(1 + 2y) - 4y = 2

2 + 4y - 4y = 2

2 = 2

This system has infinite solutions

Fifth system: 3x-4y=2; 6x-8y=1

  From the first equation: x = (2 + 4y)/3

Using this value of x in the second equation:

2*(2 + 4y) - 8y = 1

4 + 8y - 8y = 2

4 = 2

This system has no solution

5 0
3 years ago
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prohojiy [21]
3 and 11 are the answers
3 0
4 years ago
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Which equation has a slope of -4 and a y-intercept of 7.
Fiesta28 [93]

y=-4x+7

the -4 is the slope and the 7 is the y-intercept

5 0
3 years ago
Here are the monthly charges for jo’s Mobile phone. Monthly charge £16,150 free minutes,then 13p per minute,150 free texts,then
zhuklara [117]

Answer:

16,652

Step-by-step explanation:

5 0
4 years ago
Find the sum of the first 20 terms of an arithmetic series if the first term is 4 and the common difference is 3.
Ratling [72]

The sum of first 20 terms of Arithmetic Series is 650 if the first term is 4 and the common difference is 3.

Step-by-step explanation:

First Term  (a) = 4

Common difference  (d) = 3

The number of term (n) = 20

The sum of an Arithmetic series of (n) number of terms, with first term (a) and the common difference (d) is equal to

Sum =  (n/2) * ( 2 * a + (n -1) * d)

So putting the values of a,d, n

Sum = ( 20/2) * ( 2 * 4 + (20 -1) *3 )

Sum =  (10) * ( 8 + 19 * 3)

Sum =  10 * ( 8 + 57)

Sum = 10 * 65 = 650

Hence the sum of first 20 terms of Arithmetic Series is 650 if the first term is 4 and the common difference is 3.

8 0
3 years ago
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