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sergiy2304 [10]
4 years ago
7

A shop sells milk in 1 pint bottles and 2 pint bottles each 1 pint bottle of milk is 52p each 2 pint bottle of milk is 93p marti

n has non milk he assumes that he uses on average 3/4 of a pint of milk a day martin want to buy enough milk to last 7 days
Mathematics
1 answer:
Drupady [299]4 years ago
5 0
Okay so 0.75 is 3/4. you do 0.75 times 7.
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Andre45 [30]
The correct answer to the problem would be B
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3 years ago
Solve the equation: <br> - 5 = 5x + 7
HACTEHA [7]
Subtract 5x from both sides

-5x - 5 = 7
add 5 to both sides

-5x = 12

divide both sides by -5

ANSWER:
x = -2.4
8 0
3 years ago
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At the base of a pyramid, a surveyor determines that the angle of elevation to the top is °. At a point meters from the base, th
riadik2000 [5.3K]

Answer:

\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}

Step-by-step explanation:

Incomplete question:

<em></em>\angle CBD = 53^\circ<em></em>

<em></em>\angle CAB = 35^\circ<em></em>

<em></em>AB = 75<em></em>

<em></em>

<em>See attachment for complete question</em>

Required

Determine the equation to find x

First, is to complete the angles of the triangle (ABC and ACB)

\angle ABC + \angle CBD = 180 --- angle on a straight line

\angle ABC + 53= 180

Collect like terms

\angle ABC =- 53+ 180

\angle ABC =127^\circ

\angle ABC + \angle ACB + \angle CAB = 180 --- angles in a triangle

\angle ACB + 127 + 35 = 180

Collect like terms

\angle ACB =- 127 - 35 + 180

\angle ACB =18

Apply sine rule

\frac{\sin A}{a} = \frac{\sin B}{b}

In this case:

\frac{\sin ACB}{AB} = \frac{\sin CAB}{x}

This gives:

\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}

4 0
3 years ago
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In the United States, voters who are neither Democrat nor Republican are called Independent. It is believed that 11% of voters a
Radda [10]

Answer:

a) 0.0214 = 2.14% probability that none of the people are Independent.

b) 0.8516 = 85.16% probability that fewer than 6 are Independent.

c) 0.8914 = 89.14% probability that more than 2 people are Independent.

Step-by-step explanation:

For each people, there are only two possible outcomes. Either they are independent, or they are not. For each person asked, the probability of them being Independent voters is the same. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

It is believed that 11% of voters are Independent.

This means that p = 0.11

A survey asked 33 people to identify themselves as Democrat, Republican, or Independent.

This means that n = 33

A. What is the probability that none of the people are Independent?

This is P(X = 0). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{33,0}.(0.11)^{0}.(0.89)^{33} = 0.0214

0.0214 = 2.14% probability that none of the people are Independent.

B. What is the probability that fewer than 6 are Independent?

This is

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{33,0}.(0.11)^{0}.(0.89)^{33} = 0.0214

P(X = 1) = C_{33,1}.(0.11)^{1}.(0.89)^{32} = 0.0872

P(X = 2) = C_{33,2}.(0.11)^{2}.(0.89)^{31} = 0.1724

P(X = 3) = C_{33,3}.(0.11)^{3}.(0.89)^{30} = 0.2202

P(X = 4) = C_{33,4}.(0.11)^{4}.(0.89)^{29} = 0.2041

P(X = 5) = C_{33,5}.(0.11)^{5}.(0.89)^{28} = 0.1463

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0214 + 0.0872 + 0.1724 + 0.2202 + 0.2041 + 0.1463 = 0.8516

0.8516 = 85.16% probability that fewer than 6 are Independent.

C. What is the probability that more than 2 people are Independent?

This is:

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{33,0}.(0.11)^{0}.(0.89)^{33} = 0.0214

P(X = 1) = C_{33,1}.(0.11)^{1}.(0.89)^{32} = 0.0872

P(X < 2) = 0.0214 + 0.0872 = 0.1086

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1086 = 0.8914

0.8914 = 89.14% probability that more than 2 people are Independent.

8 0
3 years ago
What is the coefficient of the following term?<br> -X
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