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abruzzese [7]
3 years ago
10

Find the least LCM of 2

Mathematics
1 answer:
Serhud [2]3 years ago
5 0
There is no lcm because 2 is the least common multiple already
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PLEASE HELP FAST!!!!!!!!!
Lana71 [14]

Answer:

132 degrees

Step-by-step explanation:

To solve this problem, you need to know a couple of rules

1) Inscribed angle theroem: when an angle is inscribed in a circle and touches the other end (as opposed to ending at the diameter of the circle), the measure of this angle is half of the measure of the arc.

2)Angles of a quadrilateral shape add up to 360 degrees.

3) The angles inside a circle and the angles of the circles arclength adds up to 360 degrees.

So first, solve angle S with inscribed angle theorem. 126/2 = 63

Then, use the rule that all arc angles in a circle add up to 360 degrees to find the arc angle from Q to S. 360-90-126 = 144. Now find angle P with inscribed angle theorem by doing 144/2 = 72.

Now, use the rule that all angles in a quadrilateral add up to 360 to find R. 360-93-72-63 = 132.  

Let me know if this doesn't work, I'll look at it again.

7 0
3 years ago
What is the median of the following numbers?<br> 4, 9, 6, 3, 4, 2
kotegsom [21]

Answer:

4

Step-by-step explanation:

2,3,4,4,6,9 just find the middle number

5 0
3 years ago
Read 2 more answers
If you want to be 95​% confident of estimating the population mean to within a sampling error of plus or minus3 and the standard
Aleksandr [31]

Answer:

The sample size required is at least 171

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

What sample size is​ required?

A samle size of at least n is required, in which n is found when M = 3, \sigma = 20

So

M = z*\frac{\sigma}{\sqrt{n}}

3 = 1.96*\frac{20}{\sqrt{n}}

3\sqrt{n} = 20*1.96

\sqrt{n} = \frac{20*1.96}{3}

(\sqrt{n})^{2} = (\frac{20*1.96}{3})^{2}

n = 170.7

Rouding up

The sample size required is at least 171

5 0
3 years ago
The function h(x) is quadratic and h(3) = h(–10) = 0. Which could represent h(x)?
Lyrx [107]
I hope this helps you

6 0
3 years ago
Read 2 more answers
The equation v(x)=32500(0.92)^x how much more is the truck worth after two years than after three years
Lyrx [107]

Answer:

the difference:  $2,192.64

Step-by-step explanation:

After 1 year, the truck has lost 8% of its value:  v(x) = $32,500(0.92)^1, or

$29,900.

After 2 years, v(x) = $32,500(0.92)^2, or $27,500.  Finally, after 3 years,

v(x) = $32,500(0.92)^3 = $25,307.36.

Subtracting $25,307.36 (the value after 3 years) from $27,500 (the value after 2 years) yields the difference:  $2,192.64

6 0
3 years ago
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