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DochEvi [55]
3 years ago
13

Quadrilateral A has side lengths 6, 9, 9, and 12. Quadrilateral B is a scaled copy of Quadrilateral A, with its shortest side of

length 2. What is the scale factor from Quadrilateral A to Quadrilateral B? (write your answer as a fraction) Find all the corresponding side lengths of quadrilateral B. The side length of 6 in A corresponds to a side length of 2 in B. The side length of 9 in A corresponds to a side length of in B. The side length of 9 in A corresponds to a side length of in B. The side length of 12 in A corresponds to a side length of in B. What is the perimeter of Quadrilateral B? The perimeter of Quadrilateral B is units.
Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
7 0

Answer:

The answer is below

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, rotation and dilation.

Dilation is the increase or decrease in size of a figure. If a figure with point A(x, y) is dilated by a scale factor of k, the new location is at A'(kx, ky). If k > 1, it is an enlargement and if k < 1, it is a reduction.

a) The scale factor from Quadrilateral A to Quadrilateral B = smallest side length of side B / smallest side length of side A = 2 / 6 = 1/3

Scale factor = 1/4= 1 / 3

The side length of 6 in A corresponds to a side length of 2 in B

Side length of B that corresponds with side length of 9 in A = scale factor * 9 =  1/3 * 9 = 3

The side length of 9 in A corresponds to a side length of 3 in B

Side length of B that corresponds with side length of 12 in A = scale factor * 9 =  1/3 * 12 = 4

The side length of 12 in A corresponds to a side length of 4 in B.

c)  perimeter of Quadrilateral B = sum of side lengths of quadrilateral B = 2 + 3 + 3 + 4 = 12 units

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A small town has 2000 inhabitants. At 8 AM, 160 people have heard a rumor. By noon half the town has heard it. At what time will
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Answer:

3:36 PM

Step-by-step explanation:

Let fraction (y) of the people that heard the rumor , the differential equation that is satisfied by the by y is,

                            \frac{dy}{dt} = ky(1-y)

Solving the differential equation,

                          y(t) = \frac{y_{o}}{[y_{o} + (1 + y_{o})e^{-kt}]}

The total number of inhabitants of the town = 2000

The number of people that  heard the rumor = 160

At 8 AM, let t = 0,

               y(0) = \frac{160}{2000}

                       = 0.08

By noon, half of the town as heard the rumor.

Then,    

                y(4) = \frac{1}{2}

Therefore,

              \frac{1}{2} = \frac{0.08}{[0.08 + (1 - 0.08)e^{-4k}]}

              \frac{0.08}{[0.08 + 0.92e^{-4k}]} = \frac{1}{2}

              0.08 + 0.92e^{-4k} = 0.16  

              0.92e^{-4k} = 0.16 - 0.08

              0.92e^{-4k} = 0.08

              e^{-4k} = \frac {0.08}{0.92}

              k = - \frac{1}{4} In(\frac {0.08}{0.92})

              k ≈ 0.06106

Calculating time, t when y(t) = 90%

        ⇒ y(t) = 0.9

              \frac{0.08}{[0.08 + 0.92e^{-0.06106t}]} =0.9

              0.08 + 0.92e^{-0.06106t} = \frac {0.9}{0.08}

              0.08 + 0.92e^{-0.06106t} = 0.089

              0.92e^{-0.06106t} = 0.089 - 0.08

              0.92e^{-0.06106t} = 0.0089

              t = - \frac{1}{0.06106}In (\frac{0.0089}{0.92})

              t = 7.59 hours

              ⇒ 7 hours 36 minutes

From 8 A.M. plus 7 hours 36 minutes = 3:36 PM

At 3:36 PM will 90% of the population have heard the rumor

             

             

             

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{ \tt{f(x) =  \frac{1}{x - 5} }}

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Average rate of change:

= { \bf{ \frac{f(3) - f(-1)}{2} }}

{ \tt{ =  \frac{ -  \frac{1}{2}  - ( -  \frac{1}{6} ) }{ 2 } }} \\   \\  = { \tt{ -  \frac{1}{6} }}

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And 40 square feet so

1 x 40 = 40

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