Answer:
pH = 3.215
Explanation:
From the given information;
Using the equation for the dilution of a stock solution:
Since moles of C5H5N = moles of HNO3
Then:
The reaction between C5H5NH and H2O is as follows:
⇄ 
Now, the next step is to draw out the I.C.E table.
⇄
I 0.06333 0 0
C - x x x
E 0.06333 -x x x
![K_a = \dfrac{[C_5H_5N][H_3O^+] }{[C_5H_5N^+H] } \\ \\ 5.8824 \times 10^{-6} = \dfrac{x^2}{0.06333 - x}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cdfrac%7B%5BC_5H_5N%5D%5BH_3O%5E%2B%5D%20%7D%7B%5BC_5H_5N%5E%2BH%5D%20%7D%20%20%5C%5C%20%5C%5C%20%205.8824%20%5Ctimes%2010%5E%7B-6%7D%20%3D%20%5Cdfrac%7Bx%5E2%7D%7B0.06333%20-%20x%7D)
Assuming x < 0.06333
Then
![[H_3O^+] = x = 6.1035 \times 10^{-4} \ M \\ \\ pH = -log (6.1035 \times 10^{-4}) \\ \\ \mathbf{\\ pH = 3.215}](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%20%3D%20%20x%20%3D%206.1035%20%5Ctimes%2010%5E%7B-4%7D%20%5C%20M%20%20%5C%5C%20%5C%5C%20%20pH%20%3D%20-log%20%286.1035%20%5Ctimes%2010%5E%7B-4%7D%29%20%5C%5C%20%5C%5C%20%5Cmathbf%7B%5C%5C%20pH%20%3D%203.215%7D)
When a non-native or a foreign plant or animal is introduced in a new area, it affects the survival of the native animals that dwell there. The non-native plant or animal will compete with the native species for nutrients, water, space, food and shelter. Since the non-native animals will lack natural predators in the new habitat, they'll thrive in number. This uncontrolled competition of the non-native species with the native species will eventually leading to the death of the native species.
D)...... Hope it helps, Have a nice day:)
Adaptive radiation
occur(s) when a species gives rise to many new species after colonizing a region with diverse habitats.
I hope this helps, please give Brainest! Have a nice day!
