<h2>Hello!</h2>
The answer is:
C. Cosine is negative in Quadrant III
<h2>
Why?</h2>
Let's discard each given option in order to find the correct:
A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).
B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.
C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.
D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)
Have a nice day!
Answer:
The measure of the arc x is 130°
Step-by-step explanation:
we know that
The semi-inscribed angle is half that of the arc it comprises
so
65°=(1/2)[arc x]
solve for x
arc x=(2)(65°)=130°
Explanation:
1. It means that Nikoleta is longer and heavier than 10% of children her age.
2. We generally expect that a change from being in the 50th percentile to the 10th percentile signifies a condition that is interfering with normal growth. That is not usually considered desirable.
9u -6v = 9<-5, 1> -6<7, -4>
.. = <9*-5 -6*7, 9*1 -6*-4>
.. = <-87, 33>
The answer is the first one. 524.96 - 32.50 + x ≥ 500; x ≥ $7.54
