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4 years ago

A certain triangle has two forty-five degree angles. What type of triangle is it?

Mathematics

1 answer:

sleet_krkn [62]4 years ago

5 0

It must be a right triangle since 180° - 45° - 45° = 90°

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What is the surface area of the square pyramid represented by the net? Enter your answer in the box. m² An unfolded square base

OlgaM077 [116]

Answer:

The surface area of the square pyramid is $144\ m^{2}$

Step-by-step explanation:

we know that

The surface area of the square pyramid is equal to

$SA=B+Ph/2$

where

B is the area of the base

P is the perimeter of the base

h is the height of the pyramid

$B=6^{2}=36\ m^{2}$

<u>Find the perimeter of the base P</u>

$P=4*6=24\ m$

The height is $h=9\ m$

substitute the values

$SA=36+24*9/2=144\ m^{2}$

4 0

3 years ago

Can someone solve for x please

aleksandrvk [35]

Answer:

x=-4

Step-by-step explanation:

The two lines are parallel, so the two angles, 45 and x+49 are equal too

Lets make the equation

x+49 = 45

x = 45-49

x = -4

If my answer is incorrect, pls correct me!

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-Chetan K

8 0

3 years ago

If u help me i will thank you

uranmaximum [27]

Answer:

Step-by-step explanation:

so what you need to do is 112=16m+12b

m=magazines

b=books

6 0

3 years ago

Decrease from 126 ounces to 48 ounces

laiz [17]

78 is the answer BEST OF LUCK

8 0

3 years ago

A(5 1) b(1 5) and c(-3 -1) are the vertices of triangle abc. find the LENGTH of median ad

faltersainse [42]

Answer:

$\text{Length of median AD}=\sqrt{37}$

Step-by-step explanation:

We are given the vertices of triangle ABC. We need to find the length of median AD.

Please see the attachment for figure.

D is mid point of BC because median bisect the opposite side of triangle.

Using the formula of mid point. we get coodrinate of D

$\text{Mid Point :}\left ( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \right )$

D is mid point of B(1,5) and C(-3,-1)

$\therefore D \left ( \frac{1-3}{2},\frac{5-1}{2} \right )\Rightarrow (-1,2)$

AD is median of triangle ABC. Now we find length of median AD using distance formula of two coordinate.

$\text{Distance }=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

A(5,1) and D(-1,2)

$AD=\sqrt{(5+1)^2+(1-2)^2}\Rightarrow \sqrt{36+1}$

$\text{Length of median AD}=\sqrt{37}$

Thus, $\text{Length of median AD}=\sqrt{37}$

8 0

3 years ago