<img src="https://tex.z-dn.net/?f=6%285-8v%29%2B12%3D-54" id="TexFormula1" title="6(5-8v)+12=-54" alt="6(5-8v)+12=-54" align="ab

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Elenna [48]

2 years ago

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Mathematics

2 answers:

spayn [35]2 years ago

7 0

Answer:

v = 2

Step-by-step explanation:

Given

6(5 - 8v) + 12 = - 54 ← distribute and simplify left side

30 - 48v + 12 = - 54

42 - 48v = - 54 ( subtract 42 from both sides )

- 48v = - 96 ( divide both sides by - 48 )

v = 2

Lena [83]2 years ago

3 0

Answer:

$v = 2$

Step-by-step explanation:

$6(5-8v)+12=-54 \\ 30 - 48v + 12 = - 54 \\ 42 - 48v = - 54 \\ - 48v = - 54 - 42 \\ - 48v = - 96 \\ \\ v = \frac{( - 96)}{( - 48)} \\ \\ v = \frac{96}{48} \\ \\ v = 2$

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4z-(-3z) can you help me

Korvikt [17]

Answer:

Step-by-step explanation:

4z-(-3z).

Two negatives equal a positive only <u>when they are right next to each other.</u>

4z+3z=7z. Hope this helps :D

8 0

2 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

2 years ago

PLS HELP I NEED HELP NOW<br> I BEG

stepan [7]

Hello there! The area of the triangle portion is 11 square units, the area of the rectangle portion is 77 square units, and the area of the entire figure is 88 square units.

To find the area of the triangle, we can follow the formula:

A = LW/2 (which means length x width divided by 2)

Given the formula:

2 • 11 = 22

22 divided by 2 gives us 11 square units.

To find the area of the rectangle portion, we can follow the area formula:

A = LW (which means area = length x width)

Given the formula:

7 • 11 = 77 square units

To find the area of the whole figure, we add the areas of both isolated shapes:

11 + 77 = 88 square units.

Therefore, our area for the entire figure is 88 square units. If you need any extra help, let me know and I will gladly assist you.

7 0

1 year ago

Suppose S and T are mutually exclusive events. Find P(S or T) if P(S) = 8/9 and P(T) = 1/10.

blsea [12.9K]

Answer:

$\textbf{$P(S \cap T) = \frac{89}{90}$ }\\$

Step-by-step explanation:

$\textup{Mutually events are events that cannot occur at the same time.}\\\textup{When you toss a coin you get only $head$ or only $tail$ but never both.}\\ \textup{In mathematical terms $P(A) \cup P(B) = 0$, where $A$ and $B$ are mutually exclusive events. }\\\textup{We know the formula:}\\$$ P(A \cup B) = P(A) + P(B) - P(A \cup B) $$\\\textup{When $A$ and $B$ are mutually exclusive, it will simply be:}\\$$ P(A \cup B) = P(A) + P(B) $$\\\textup{Now given:}\\ $P(S) = 8/9$ , $P(T) = 1/10$\\$

$\implies P(S \cup T) = \frac{89}{10}$

6 0

2 years ago

What is the measure of angle I, m

strojnjashka [21]

Answer:

angle I =110

70 +I = 180 (opp side of parallelogram are equal)

I = 180 - 70

angle I =110

3 0

2 years ago