All categories

3 years ago

The graph of sqrt of x has symmetry but the graph of - square root x does not true or false

1 answer:

6 0

Answer: False

Neither y = sqrt(x) nor y = -sqrt(x) has any symmetry. The curves continue onward to the right and do not come back in any sort of mirrored fashion.

You might be interested in

How are the side lengths of a right triangle and the side lengths of a square related????/

madam [21]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the Answer <br> Please Help

sergejj [24]

Answer:

Step-by-step explanation:

circumference=2πr

=2*3.14*2

=12.56 km

3 0

2 years ago

One thousand independent rolls of a fair die will be made. Compute an approximation to the probability that the number 6 will ap

pashok25 [27]

Answer:

0.19

Step-by-step explanation:

We are given that

Number of rolls of die=n=1000

Let the event of six coming up be success.Then, in each trial , the probability of success =p=P(success)=P(6)= $\frac{1}{6}$

Let X be the random variable for the number of sixes in the 1000 rolls of die.

Then, $X\sim Binom(1000,\frac{1}{6})$

Since, n is very large,the binomial random variable can be approximated as normal random variable.

Mean, $\mu=np=1000\times \frac{1}{6}=166.67$

Variance= $\sigma^2=np(1-p)=1000\times \farc{1}{6}\times (1-\frac{1}{6})=1000\times \frac{5}{36}=138.89$

$X\sim N(166.67,138.89)$

$P(150\leq X\leq 200)=P[\frac{150-166.67}{11.79}\leq \frac{X-\mu}{\sigma}\leq \frac{200-166.67}{11.79}]$

= $P[-1.41\leq Z\leq 2.83]=P[Z\leq 2.83]-P[Z$

= $\phi(2.83)-\phi(-1.41)$

=0.9977-0.0793=0.9184

Thus, the probability that the number 6 appears between 150 to 200 times=0.92

Now, given that 6 appears exactly 200 times .

Therefore, other number appear in other 800 rolls .

We have to find the probability that the number 5 will appear less than 150 times.

Therefore, for 800 rolls, let the event of 5 coming up be success.

Then , p=P(success)=P(5)= $\frac{1}{5}$

Let Y be the random variable denoting the number of times 5 coming up in 800 rolls.

Then, $Y\sim bin(800,\frac{1}{5})$

Mean, $\mu=np=800\times \frac{1}{5}=160$

Variance, $\sigma^2=np(1-p)=800\times \frac{1}{5}(1-\frac{1}{5})=128$

$Y\sim N(160,128)$ because n is large

$P(Y$

$P(Y$

Hence, the probability that the number 5 will appear less than 150 times given that 6 appeared exactly 200 times=0.19

4 0

3 years ago

What are the x-intercepts of this function f(x)=x^2+5x-36?

Gnom [1K]

F(x)=x2+5x−36f(x)=x2+5x-36
(0)=x2+5x−36(0)=x2+5x-36
x=4,−9x=4,-9
y=(0)2+5(0)−36y=(0)2+5(0)-36
y=0+0−36y=0+0-36
y=−36y=-36
These are the xx and yy intercepts of the equation y=x2+5x−36y=x2+5x-36.
x-int: (4,0),(−9,0)(4,0),(-9,0)
y-int: (0,−36)(0,-36)

4 0

3 years ago

What is the volume of the smallest square-based prism that would hold this cylinder?

Lynna [10]

Answer:

The answer to your question is Volume = 80000 cm³

Step-by-step explanation:

Data

height = 50 cm

radius = 20 cm

Process

1.- The smallest dimensions of the prism must have the same dimensions that the cylinder.

Radius = 20 cm then the length of a side = 2 x radius = 40 cm

2.- Calculate the area of the base

Area = 40 x 40

= 1600 cm²

3.- Calculate the volume of the prism

Volume = Area x height

= 1600 x 50

= 80000 cm²

4 0

3 years ago