Answer:
=−15a2c7−12a3c4+24a2c4
Step-by-step explanation:
Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
11
Step-by-step explanation:
5x + 5 = 4x + 16 ( being alternate angles)
5x - 4x = 16 - 5
x = 11
Hope it will help :)
Answer:
<h2>24 students</h2>
Step-by-step explanation:
25% of a hundred is one-fourth and because there are six students in a fourth of the whole we are multiplying four and six. 6x 4 is 24.
Answer:
81.2222 or 81 with 2 left over
Step-by-step explanation:
731/9 = 81.2222
81.2222 rounded down = 81
9*81 = 729
731-729 = 2 left over
This is the third time I am answering the question.
