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2 years ago

What are the AGI and taxable income?

Mathematics

2 answers:

Sholpan [36]2 years ago

8 0

Answer:

$35,468 and $27,268

Step-by-step explanation:

andreev551 [17]2 years ago

3 0

Answer:

1. Find the AGI and taxable income: Gross Income $30,856 Adjustments $750 1 Exemption $8200 Deduction $2,300

AGI: $31,200 and $20,601 $30106 --- ANSWER: 30,106 (30,856-750)

Taxable Income: $19,606 $29,586 and $18,505 $28,863 and $17,636 1 points--- ANSWER 19,606

2. QUESTION 5 Find the AGI and taxable income. Gross Income $67,890

Adjustments $0 3 Exemptions $24,600 Deduction $1469

AGI: $69,440 and $45,300 $68,990 and $42,831 $67,890 --- ANSWER:

67,890

Taxable Income: $41,821 $65,551 and $44,821 1 points --- ANSWER: 41,821 (67,890-24,600-1,469)

3. QUESTION 6 Find the AGI and taxable income. Gross income $19,723 Adjustments $255 1 Exemption $8200 Deduction $1430 $19,4

AGI: 19,468 (19,723-255)

Taxable Income: 9,838 (19,468-8,200-1,430)

Step-by-step explanation:

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2 years ago

Let u = (1, 2 -2), v= (2, 1, 3) and w = j + 4k. a) Find cos theta, where theta is the angle in degrees between u and w.

vodka [1.7K]

Answer: The value of cos theta is -0.352.

Step-by-step explanation:

Since we have given that

$\vec{u}=1\hat{i}+2\hat{j}-2\hat{k}\and\\\\\vec{w}=\hat{j}+4\hat{k}$

We need to find the cos theta between u and w.

As we know the formula for angle between two vectors.

$\cos\ \theta=\dfrac{\vec{u}.\vec{w}}{\mid u\mid \mid w\mid}$

So, it becomes,

$\cos \theta=\dfrac{2-8}{\sqrt{1^2+2^2+(-2)^2}\sqrt{1^2+4^2}}\\\\\cos \theta=\dfrac{-6}{\sqrt{17}\sqrt{17}}=\dfrac{-6}{17}=-0.352\\\\\theta=\cos^{-1}(\dfrac{-6}{17})=110.66^\circ$

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3 years ago

Which of the following pairs of functions are inverses of each other?

AnnyKZ [126]

Answer:

Step-by-step explanation:

Rearrange each function to solve for x.

Switch x and y,

The resulting equation is the inverse function.

f(x) = y = 5+x

x = y-5

y = x-5

f⁻¹(x) = x-5

g(x) = 5-x ≠ f⁻¹(x)

g(x) is not the inverse of f(x).

:::::

f(x) = y = 2x-9

x = (y+9)/2

y = (x+9)/2

f⁻¹(x) = (x+9)/2

g(x) = (x+9)/2 = f⁻¹(x)

g(x) is the inverse of f(x).

:::::

f(x) = y = 2/x - 6

x = 2/(y+6)

y = 2/(x+6)

f⁻¹(x) = 2/(x+6)

g(x) = (x+6)/2 ≠ f⁻¹(x)

:::::

f(x) = y = x/3 + 4

x = 3y - 12

y = 3x - 12

f⁻¹(x) = 3x - 12

g(x) = 3x - 4 ≠ f⁻¹(x)

g(x) is not the inverse of f(x).

4 0

2 years ago