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Evgen [1.6K]
3 years ago
8

Mitchell invested part of his $34,000 advance at 2% annual simple interest and the rest at 9% annual simple interest. If his tot

al yearly interest from both accounts was $2,570, find the amount invested at each rate.
Invested at 2%: $________
Invested at 9%: $________
Mathematics
1 answer:
slava [35]3 years ago
8 0
Let x = Amount invested at 2%
      y = Amount invested at 9%

x + y = 34000            ×(-0.02)→ -0.02x - 0.02y = -680
0.02x + 0.09y = 2570             →  0.02x + 0.09y = 2570
                      add the equations               0.07y = 1890
           divide by 0.07 both sides                      y = 27000
x = 34000 - 27000 = 7000
ANSWER:
Invested at 2%: $7000
Invested at 9%: $27000
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