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NeTakaya
3 years ago
15

(3x-8)° (4x-23)° fine the x

Mathematics
1 answer:
Veronika [31]3 years ago
7 0

You cannot find x.

Because both phrases are to the power of 0, we know that it is essentially 1*1

So:

(3x - 8)^0 (4x - 23)^0 = 1

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Write an expression for the calculation subtract 10 divided into fifths from 20 diveded in half
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20/2-10/5. You divide 20 by 2 and subtract that from 10 divided by 5
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-3y-3x=-3<br><br><br><br><br>plz help me​
brilliants [131]

Answer:

y = -x + 1

Step-by-step explanation:

-3y - 3x = -3

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-3y = 3x - 3

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Find all solutions of the equation in the interval [0, 2pi).
mina [271]

Answer:

x = 0 , π

Step-by-step explanation:

-4 \sin x = 1 - cos^2 x

  • Rewrite it by using the identity \sin^2x + \cos^2x = 1

=> -4\sin x = \sin^2x

  • Add 4sin x to both the sides.

=> -4\sin x + 4\sin x = sin^2x + 4\sin x

=> \sin^2x + 4\sin x = 0

  • Take sin x common from the expression in L.H.S.

=> \sin x(\sin x + 4)=0

Here , we can get two more equations to find x.

1) \sin x(\sin x + 4)=0

  • Divide both the sides by sin x

=> \frac{\sin x(\sin x + 4)}{\sin x} = \frac{0}{\sin x}

=> \sin x + 4 = 0

  • Substract 4 from both the sides.

=> \sin x + 4 - 4 = 0 - 4

=> \sin x = -4

=> x = No \; Solution

2) \sin x(\sin x + 4)=0

  • Divide both the sides by (sin x + 4)

=> \frac{\sin x(\sin x + 4)}{\sin x + 4} = \frac{0}{\sin x + 4}

=> \sin x =  0

=> x = 0 \; , \pi over interval [0 , 2π).

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3 years ago
16) The angles of a quadrilateral are in AP, whose common difference is 10°.
Oksanka [162]

Answer:

75°, 85°, 95°, 105°

Step-by-step explanation:

Since the 4 angles form an AP, then the 4 angles are

a, a + d, a + 2d, a + 3d

where a is the first term and d the common difference

The sum of the angles in a quadrilateral = 360° thus

a + a + d + a + 2d + a + 3d = 360, that is

4a + 6d = 360, substitute d = 10

4a + 60 = 360 ( subtract 60 from both sides )

4a = 300 ( divide both sides by 4 )

a = 75

Thus the 4 angles are

75°, 75° + 10° = 85°, 75° + 20 = 95°, 75° + 30° = 105°

8 0
3 years ago
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