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Kaylis [27]
3 years ago
7

Circle P has center P(2,0) and a radius 20. Circle Q has center Q(0,4) and radius 2. Describe the rule for translating center Q

onto center P. Determine the scale factor for dilating circle Q so that it has the same radius as circle P. Are circles P & Q similar? Explain your answer
Mathematics
1 answer:
fomenos3 years ago
8 0
The circle the has a center P(2,0) is bigger than compared to the circle with the center Q(0,4) because the former has a radius 20, while the latter has a radius of only 2. You can view the graph here: 
https://www.desmos.com/calculator/od1pwqylou

(a) Describe the rule for translating center Q onto center P. By moving the center of circle Q overlapping the center of circle P, then we need to move it two units left and 4 units up.

(b) Determine the scale factor for dilating circle Q so that it has the same radius as circle P. In getting the scale factor, we need to compare the radius
= 2/10
= 1/10
So, the scale factor is 1/10

(c) Are circles P and Q similar? Explain your answer.
Yes, by applying a dilation value, circle Q can be transformed to circle P, vice versa.
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This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.

Area of a rectangle:

The area of rectangle of length l and width w is given by:

A = wl

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l = 2w + 3, A = 9

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

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x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

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In this question:

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w_{1} = \frac{-3 + \sqrt{81}}{2*2} = 1.5

w_{2} = \frac{-3 - \sqrt{81}}{2*2} = -3

Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.

Another similar problem can be found at brainly.com/question/16995958

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