Im mot sure of the answer
We know that the first cyclist has traveled 24.2 km at a speed of 10 km/h. Lets use the equation

to find the time of the first cyclist:


So, we know that she has traveled for 2.42 hours.
We also know that after she has traveled for 2.42 hours another<span> cyclist sets out in the same direction, so if </span>

represents the time of our first cyclist, <span>the time of our second cyclist will be </span>

.
Now we are going to use the equation

to relate the speeds and times of the two cyclist:
For the first one:

equation (1)
For the second one:

equation (2)
Replace (1) in (2)

The only thing left now is solve for

:




We can conclude that the second cyclist will catch up the first cyclist after
3.63 hours.
Answer:
4.57
Step-by-step explanation:
There are 10 lines in between 4.5 and 4.6, so we can assume each line adds 0.01
<span>2x + 5y = 10
5y = -2x + 10
y = -2/5 x + 2
so slope = -2/5
</span><span>passes through the point (5, −4)
</span><span>y = mx + b
b = y - mx
b = -4 - (-2/5)(5)
b = -4 + 2
b = -2
equation
y = -2/5 x - 2
hope it helps
</span>
First you need to find the slope, which is (y2-y1)/(x2-x1)
Plug the points in as (1-4)/(-1-1) -> -3/-2
The slope is 3/2, or 1.5
Point slope form is y-y1 = m(x-x1)
Plug in the slope (m) and the first point
y-4 = 1.5(x-1) <-- That's point slope form
To get standard form (ax+by=c), you can use point slope form
y - 4 = 1.5(x - 1)
y - 4 = 1.5x - 1.5
y = 1.5x + 2.5
-1.5x + y = 2.5 <-- Standard Form