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Ksenya-84 [330]
3 years ago
11

The solution of 4(x + 1) = 4(2 – x)

Mathematics
2 answers:
Pavel [41]3 years ago
7 0

Step-by-step explanation:

4x+4=8-4x

4x+4+(4x)=8-4x+(4x)

8x+4-(4)=8-(4)

8x÷(8)=4÷(8)

x=0.5 or 1/2

Galina-37 [17]3 years ago
5 0

4x+4=8-4x

4x+4x=8-4

8x=4

x=4/8

x=1/2

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victus00 [196]

Answer:

-0.55n - 0.05

Step-by-step explanation:

You can start by distributing:

(0.25n - 0.3) - (0.8n - 0.25)

0.25n - 0.3 - 0.8n + 0.25

Then, you can combine like terms(0.25n & -0.8n; -0.3 & 0.25)

-0.55n - 0.05

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3 years ago
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Answer: I'm not sure but there's some explanation..

Step-by-step explanation:

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7 0
3 years ago
Which function is a quadratic function? A. c(x) = 6x + 3x3 B. d(x) = x – 8x4 C. p(x) = –5x – x2 D. k(x) = 2x2 + 9x4
Sati [7]
<h3>Answer: C.  p(x) = -5x-x^2</h3>

This is the same as p(x) = -x^2-5x

The degree is the largest exponent to determine what kind of polynomial we're dealing with.

For choice C, the degree is 2, so we have a quadratic here.

-----------

Extra info:

  • Choice A is cubic because the largest exponent is 3 (degree = 3)
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  • Choice D is the same story as choice B

6 0
3 years ago
The surface area of yringaler prism​
Trava [24]

Answer:

180 cm

Step-by-step explanation:

2(3*10) = 60

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7 0
3 years ago
Determine the above sequence converges or diverges. If the sequence converges determine its limit​
marshall27 [118]

Answer:

This series is convergent. The partial sums of this series converge to \displaystyle \frac{2}{3}.

Step-by-step explanation:

The nth partial sum of a series is the sum of its first n\!\! terms. In symbols, if a_n denote the n\!th term of the original series, the \! nth partial sum of this series would be:

\begin{aligned} S_n &= \sum\limits_{k = 1}^{n} a_k \\ &=  a_1 + a_2 + \cdots + a_{k}\end{aligned}.

A series is convergent if the limit of its partial sums, \displaystyle \lim\limits_{n \to \infty} S_{n}, exists (should be a finite number.)

In this question, the nth term of this original series is:

\displaystyle a_{n} = \frac{{(-1)}^{n+1}}{{2}^{n}}.

The first thing to notice is the {(-1)}^{n+1} in the expression for the nth term of this series. Because of this expression, signs of consecutive terms of this series would alternate between positive and negative. This series is considered an alternating series.

One useful property of alternating series is that it would be relatively easy to find out if the series is convergent (in other words, whether \displaystyle \lim\limits_{n \to \infty} S_{n} exists.)

If \lbrace a_n \rbrace is an alternating series (signs of consecutive terms alternate,) it would be convergent (that is: the partial sum limit \displaystyle \lim\limits_{n \to \infty} S_{n} exists) as long as \lim\limits_{n \to \infty} |a_{n}| = 0.

For the alternating series in this question, indeed:

\begin{aligned}\lim\limits_{n \to \infty} |a_n| &= \lim\limits_{n \to \infty} \left|\frac{{(-1)}^{n+1}}{{2}^{n}}\right| = \lim\limits_{n \to \infty} {\left(\frac{1}{2}\right)}^{n} =0\end{aligned}.

Therefore, this series is indeed convergent. However, this conclusion doesn't give the exact value of \displaystyle \lim\limits_{n \to \infty} S_{n}. The exact value of that limit needs to be found in other ways.

Notice that \lbrace a_n \rbrace is a geometric series with the first term is a_0 = (-1) while the common ratio is r = (- 1/ 2). Apply the formula for the sum of geometric series to find an expression for S_n:

\begin{aligned}S_n &= \frac{a_0 \cdot \left(1 - r^{n}\right)}{1 - r} \\ &= \frac{\displaystyle (-1) \cdot \left(1 - {(-1 / 2)}^{n}\right)}{1 - (-1/2)} \\ &= \frac{-1 +  {(-1 / 2)}^{n}}{3/2} = -\frac{2}{3} + \frac{2}{3} \cdot {\left(-\frac{1}{2}\right)}^{n}\end{aligned}.

Evaluate the limit \displaystyle \lim\limits_{n \to \infty} S_{n}:

\begin{aligned} \lim\limits_{n \to \infty} S_{n} &= \lim\limits_{n \to \infty} \left(-\frac{2}{3} + \frac{2}{3} \cdot {\left(-\frac{1}{2}\right)}^{n}\right) \\ &= -\frac{2}{3} + \frac{2}{3} \cdot \underbrace{\lim\limits_{n \to \infty} \left[{\left(-\frac{1}{2}\right)}^{n} \right] }_{0}= -\frac{2}{3}\end{aligned}}_.

Therefore, the partial sum of this series converges to \displaystyle \left(- \frac{2}{3}\right).

8 0
3 years ago
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