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solong [7]
3 years ago
7

Which expression is equivalent to t2 – 36?

Mathematics
2 answers:
sveticcg [70]3 years ago
5 0
Factor <span><span>t2</span>−36</span><span><span>t2</span>−36</span><span>=<span><span>(<span>t+6</span>)</span><span>(<span>t−6</span>)

</span></span></span>Answer:<span><span>(<span>t+6</span>)</span><span>(<span>t−6</span>)</span></span><span>
Good luck mate :P</span>
WITCHER [35]3 years ago
3 0

Answer:

t^2-36=(t+6)(t-6)

Step-by-step explanation:

the expression we have is:

t^2-36

which can be rewritten as:

t^2-6^2

this is because 36=6^2

the equation t^2-6^2 is known as a Difference of squares, because we have a substraction of two elements squared.

And in a general form a Difference of squares is equivalent to:

a^2-b^2=(a+b)(a-b)

so in this case we can write t^2-6^2 as:

t^2-6^2=(t+6)(t-6)

ang going back to the original expression t^2-36, we have:

t^2-36=(t+6)(t-6)

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vichka [17]

4 cos² x - 3 = 0

4 cos² x = 3

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Fixing the squared cosine doesn't discriminate among quadrants.  There's one in every quadrant

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Let's do plus first.  In general, cos x = cos a has solutions x = ±a + 2πk integer k

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x = ±π/6 + 2πk

Minus next.

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cos x = cos(π - π/6)

cos x = cos(5π/6)

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We'll write all our solutions as

x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k

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What are the first 10 digits after the decimal point when the fraction $\frac17$ is written in base 16?
Virty [35]

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The amswer is "2,4,9....."

Step-by-step explanation:

x=\frac{1}{7}\\\\x_d=0.\overline{142857}\\\\x_h=0.\overline{249}\\\\

by leave you to work out the other 7 digits:

\to \frac{1}{7}\approx \frac{a}{16}\\\\a= \text{first hex digit}\\\\a=floor(\frac{16}{7})=2\\\\  

\to \frac{1}{7}- \frac{a}{16}\approx \frac{b}{16^2}\\\\b= \text{second hex digit}\\\\b=floor(\frac{16^2}{7} -16a)=4\\\\  

\to \frac{1}{7}- \frac{a}{16}-\frac{b}{16^2} \approx \frac{c}{16^3}\\\\c= \text{third hex digit}\\\\c=floor(\frac{16^3}{7} -16^2a-16b)=9\\\\  

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72 ፥ 3² x 2² + 36 ፥ 9 =
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