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Murrr4er [49]
3 years ago
12

Please answer correctly !!!! Will mark brainliest !!

Mathematics
2 answers:
jek_recluse [69]3 years ago
5 0

Answer:

h(u)=-7/6u

Step-by-step explanation:

To write a formula for v in terms of u, you need to first isolate v.

4u+8v=-3u+2v

Add 3u to both sides:

7u+8v=2v

Subtract 8v from both sides:

7u=-6v

Divide both sides by -6:

v=-7/6u

Hope this helps!

ExtremeBDS [4]3 years ago
5 0

Answer:

u= - 6v

      7

Step-by-step explanation

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P is inversely proportional to Q.
Volgvan
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7 0
3 years ago
Mrs. Speas has $138 in her bank account during Week #1. At the end of each week, she deposits $55 into her bank account. What is
nordsb [41]

The first term is 138

The difference is 55

The iterative rule for the amount of money Mr Speas has after n weeks is

55/2 n² + 221/2 n

During the first week she has $138 in his bank account. At the end of each week she deposited $55 into her bank account.

The first term will be 138 .

The common difference is 55 because her bank always increase by $55 dollars every week. The sequence will be 138, 193, 248, 303, 358...…

The difference = 193 - 138 = 55.

The iterative rule for the amount of money Mr Speas has after n weeks can be represented  below

n = number of weeks

a = first term = 138

d = common difference = 55

Using AP formula,

sₙ = n/2(2a + (n - 1)d)

sₙ = n/2 (2(138)+ (n - 1)55)

sₙ = n /2(276 + 55n -55)

sₙ = n /2(221 + 55n)

sₙ = 55/2 n² + 221/2 n

read more: brainly.com/question/20373665?referrer=searchResults

6 0
2 years ago
Read 2 more answers
For n = 3, what are the possible sublevels?
PilotLPTM [1.2K]
N represents the quantum number. for n = 3, there are 3 possible sublevels that are 3s, 3p and 3d.
There are four sublevels that are s, p, d and f. In s subshell or sublevel there is 1 orbital, in p sublevel there is 3 orbitals, in d sublevel there is 5 orbitals and in d sublevel there is 7 orbitals. 
And there are 2, 6, 10 and 14 maximum number of electrons in s, p, d and f sublevels respectively.
3 0
3 years ago
A survey of 132 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take
ddd [48]

Answer:

For 90% CI = (0.428, 0.572)

For 98% CI = (0.399, 0.601)

The confidence interval (and Margin of error) reduces when 90% confidence level is used compared to when 98% confidence level is used.

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

p+/-z√(p(1-p)/n)

Given that;

Proportion p = 66/132 = 0.50

Number of samples n = 132

Confidence level = 90%

z(at 90% confidence) = 1.645

Substituting the values we have;

0.50 +/- 1.645√(0.50(1-0.50)/132)

0.50 +/- 1.645√(0.001893939393)

0.50 +/- 0.071589436011

0.50 +/- 0.072

(0.428, 0.572)

The 90% confidence level estimate of the true population proportion of students who responded "yes" is (0.428, 0.572)

For 90% CI = (0.428, 0.572)

For 98% CI = (0.399, 0.601)

The confidence interval (and Margin of error) reduces when 90% confidence level is used compared to when 98% confidence level is used.

7 0
3 years ago
How many real number solutions are there to the equation 0=-3x^2 + x -4
natta225 [31]
We have that
<span>the equation
y=-3x</span>²<span> + x -4
the </span><span>real number solutions are the points x intercept of the graph
are the points when y=0

using a graph tool
see the attached figure

</span><span>the graph has no point of intersection with the x axis
</span>therefore

the answer is
there are zero real numbers solutions

8 0
3 years ago
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