All categories

4 years ago

What is the value of x if 46=6x-2

Mathematics

2 answers:

alukav5142 [94]4 years ago

4 0

The answer would be x=8

Irina-Kira [14]4 years ago

3 0

46=6x−2
You should simplify first.
(flip the equation if you want; 6x-2=46)
Add 2 to both sides
46(+2)=6x(+2)
48=6x
Divide both sides by 6.
48/6=6x/6
8=x
x=8

You might be interested in

At the afternoon matinee movie, 2 adult tickets and 4 child tickets cost $32, and 4 adult tickets and 3 child tickets cost $44.

Yuliya22 [10]

Answer:

2x + 4y = 32

4x + 3y = 44

Step-by-step explanation:

From the information supplied in the question, we can see that 2 adult tickets and 4 child tickets cost $32. This means we multiply the cost of an adult ticket by 2 and add it to the product of 4 child tickets and its price I.e y.

We can also see that to get a total cost of $44, 4 adult tickets and 3 child tickets were bought. Hence, we simply multiply the cost of an adult ticket by 4 and add it to the product of 3 child ticket and its price

8 0

3 years ago

A taxi company charges passengers $2.00 for a ride, and an additional $0.50 for each mile traveled. The function rule = 0.50 + 2

stellarik [79]

Answer:

The graph of the function rule will be a line segment connecting (0,2) and (40,22) as shown in the graph below.

Step-by-step explanation:

The graph of the function rule will be a line segment connecting (0,2) and (40,22) as shown in the graph below.

5 0

3 years ago

Does anyone know how to tell if a graph is inverse

Rainbow [258]

Step-by-step explanation:

A function f(x) has an inverse, or is one-to-one, if and only if the graph y = f(x) passes the horizontal line test. A graph represents a one-to-one function if and only if it passes both the vertical and the horizontal line tests.

8 0

3 years ago

Read 2 more answers

The second sample was the same size as the first, and the proportion of sales identified as organic was 0.4. How does the 95 per

enot [183]

Answer:

The summer interval is wider and has a greater point of estimate

Step-by-step explanation:

Assuming this problem: "An environmental group wanted to estimate the proportion of fresh produce sales indentified as organic in a grocery store. In the winter, the group obtained a random sample of sales from the store and used the data to construct a 95percent z-interval for a proportion (0.087,0.133). Six months later in the summer, the group obtained a second random sample of sales from the store. The second sample was the same size as the first, and the proportion of sales identified as organic was 0.4. How does the 95 percent z-interval for a proportion constructed from the summer sample compare to the winter interval? "

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

We can find the margin of error from the interval given on this case would be:

$ME= \frac{0.133-0.087}{2}=0.023$

And the point of estimate for the proportion obtained would be:

$\hat p = 0.133-0.023=0.11$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =0.023$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.11(1-0.11)}{(\frac{0.023}{1.96})^2}=710.95$

And rounded up we have that n=711

Now we know that we use the same sample size for the new confidence interval. And replacing into the confidence interval formula we got:

$0.4 - 1.96 \sqrt{\frac{0.4(1-0.4)}{711}}=0.364$

$0.4 + 1.96 \sqrt{\frac{0.4(1-0.4)}{711}}=0.436$

And the new 95% confidence interval would be given (0.364;0.436) has a width of 0.436-0.364=0.072. And the width for the previous confidence interval is 0.133-0.087= 0.046. So then the best answer is:

The summer interval is wider and has a greater point of estimate

7 0

3 years ago

Please help me simplify this equation!

vladimir1956 [14]

X^2(x+4) x 3x^2(x-1)
(X^3+4x^2) x (3x^3 -3x^2)
3x^6 -3x^5+12x^5 -12x^4
3x^6 +9x^5-12x^4
I think that’s how you do it

3 0

4 years ago