Answer:
Solution given:
f(x) =
x-2
let f(x)=y
y =
x-2
interchanging role of x and y
x=
y-2
x+2=
y
y=9(x+2)
y=9x+18
So
<u>F</u><u>-</u><u>¹</u><u>(</u><u>x</u><u>)</u><u>=</u><u>9</u><u>x</u><u>+</u><u>1</u><u>8</u>
<u>a</u><u>n</u><u>d</u>
<u>F</u><u>-</u><u>¹</u><u>(</u><u>-</u><u>1</u><u>)</u><u>=</u><u>9</u><u>*</u><u>-</u><u>1</u><u>+</u><u>1</u><u>8</u><u>=</u><u>-</u><u>9</u><u>+</u><u>1</u><u>8</u><u>=</u><u>9</u>
Answer:
The probability they have one boy and one girl = 0.50 = 50 %
Step-by-step explanation:
Here the family has two children, we need to find what is the probability they have one boy and one girl.
Probability for babies are boys = 51.3% = 0.513
Probability for babies are girls = 1 - 0.513 = 0.487
The probability they have one boy and one girl = 1 - probability that they have two boys - probability that they have two girls
The probability they have one boy and one girl = 1 - 0.513² - 0.487² = 0.499 = 0.50
The probability they have one boy and one girl = 0.50 = 50%
Answer:
Step-by-step explanation:
2 7/8 = 23/8
2 1/4 = 9/4
23/8 / 9/4 =
23/8 * 4/9 = 92/72 = 1 20/72 = 1 5/18
Answer:
B
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is

Here [ a, b ] = [ - 1, 6 ] and from the graph
f(b) = f(6) = 0
f(a) = f(- 1) = 0, thus
average rate of change =
=
= 0