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alexdok [17]
4 years ago
5

Please help me simplify this equation!

Mathematics
1 answer:
vladimir1956 [14]4 years ago
3 0
X^2(x+4) x 3x^2(x-1)
(X^3+4x^2) x (3x^3 -3x^2)
3x^6 -3x^5+12x^5 -12x^4
3x^6 +9x^5-12x^4
I think that’s how you do it
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If f(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D" id="TexFormula1" title="\frac{1}{9}" alt="\frac{1}{9}" align=
boyakko [2]

Answer:

Solution given:

f(x) = \frac{1}{9} x-2

let f(x)=y

y = \frac{1}{9} x-2

interchanging role of x and y

x= \frac{1}{9} y-2

x+2= \frac{1}{9} y

y=9(x+2)

y=9x+18

So

<u>F</u><u>-</u><u>¹</u><u>(</u><u>x</u><u>)</u><u>=</u><u>9</u><u>x</u><u>+</u><u>1</u><u>8</u>

<u>a</u><u>n</u><u>d</u>

<u>F</u><u>-</u><u>¹</u><u>(</u><u>-</u><u>1</u><u>)</u><u>=</u><u>9</u><u>*</u><u>-</u><u>1</u><u>+</u><u>1</u><u>8</u><u>=</u><u>-</u><u>9</u><u>+</u><u>1</u><u>8</u><u>=</u><u>9</u>

6 0
3 years ago
t is commonly assumed that babies are equally likely to come as either a boy or a girl. This is not true. Actually, about 51.3%
eduard

Answer:

The probability they have one boy and one girl = 0.50 = 50 %

Step-by-step explanation:

Here the family has two children, we need to find what is the probability they have one boy and one girl.

Probability for babies are boys = 51.3% = 0.513

Probability for babies are girls = 1 - 0.513 = 0.487

The probability they have one boy and one girl = 1 -  probability that they have two boys - probability that they have two girls

The probability they have one boy and one girl = 1 - 0.513² - 0.487² = 0.499 = 0.50

The probability they have one boy and one girl = 0.50 = 50%

7 0
3 years ago
The (T) total number of dollars in (1) five-dollar bills and (t) ten-dollar bills is:
OlgaM077 [116]

Answer:

Step-by-step explanation:

5 0
3 years ago
2 7/8 divided by 2 1/4
trasher [3.6K]

2 7/8 = 23/8

2 1/4 =  9/4

23/8 / 9/4 =

23/8 * 4/9 = 92/72 = 1 20/72 =  1 5/18

5 0
3 years ago
(AP Calc) the graph of the function f shown above has three line segments....
I am Lyosha [343]

Answer:

B

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ - 1, 6 ] and from the graph

f(b) = f(6) = 0

f(a) = f(- 1) = 0, thus

average rate of change = \frac{0-0}{6+1} = \frac{0}{7} = 0

7 0
3 years ago
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