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ivann1987 [24]
3 years ago
6

E-Z View cable company charges a flat rate of $40 per month for service and $4.95 for each pay per view movie. View the Best cha

rges a flat rate of $25 per month and $5.95 for each pay per view. Using the given equations, how many pay per views will generate equal monthly bills from the two companies?
Mathematics
1 answer:
kkurt [141]3 years ago
6 0
E-Z View: 40 + 4.95x
View the best: 25 + 5.95x

Equal monthly bills:

40 + 4.95x = 25 + 5.95x

5.95x - 4.95x = 40 - 25

x = 15

Answer: 15
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Write each number in scientific notation.
Afina-wow [57]
1,050,200

The number between 1 and 10: 1
The power of 10: 6
The number in scientific notation: 1.05^6 or 1.050200^6

34,600

The number between 1 and 10: 3
The power of 10: 4
The number in scientific notation: 3.46^4
3 0
3 years ago
Sigmund wrote four checks last month, and these were the only transactions for his checking account. According to his check regi
Lady bird [3.3K]

Answer:

The Check that hasn't been cleared yet is for $372.15.

Step-by-step explanation:

168.48+ 168.93+ 177.78+ 177.93= 693.12

887.79- 693.12= 194.67

1,065.27- 887.79= 177.48

194.67+ 177.48= 372.15

To check your answer:

372.15+ 693.12= 1,065.27

Hope this helped you!! (:

7 0
3 years ago
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The area of a triangle that has a base of 7 and a height of 17 is:
Andru [333]

Answer:

59.5

Step-by-step explanation:

First we have to multiply 7 by 17 (7x17).

Then you have to divide it by 2.

1/2 X base x height

8 0
1 year ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
If the temperature outside is 25c what clothing would be the most appropriate
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Jacket, beanie, snow boots
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