Answer:
H=9;8)
B=(5;4) (ball)
R=(7;0) (hit point)
B'=symetric of B axis perpendicular of x in R
B'=(7+(7-5);4)=(9;4)
Equation BR: y-4=(0-4)/(7-5)(x-5)==>y=-2x+14
Equation RB': y-4=(4-0)/(9-7)(x-9)==>y=2x-14
Is H a point of RB'? y=2x-14 : 8=? 2*9-14==>8=?4 No!
you will not make your putt
Step-by-step explanation:
8x^2 - 16x - 15 = 0
x = [ -(-16) +/- sqrt((-16)^2 - 4*8*-15) / ] 2*8
= 2.696, -0.696
Answer: 1,4 is the answer
Answer:
-2x+-8-3x-8
Step-by-step explanation:
-2 times x =-2x
-2 times 4=-8
Answer:
563.55
Step-by-step explanation:
85/100*663=563.55