Question

A plumber earns $50 for a repair job, plus an additional $75 per hour he works. On Tuesday, he completed 3 repair jobs and earned a total of more than $600.
Part A Write an inequality that can be used to determine h, the number of hours the plumber worked Tuesday
Part B: Solve your inequality to determine the number of hours the plumber worked Tuesday. Provide mathematical justification for your answer.

Answer 1

Answer:

A. $150+75h>600$

B. More than 6 hours

Step-by-step explanation:

A plumber earns $50 for a repair job, so he will earn $150 for three repair jobs.

Let h be the number of hours the plumber worked on Tuesday. He earns $75 per hour worked, so he will earn $75h in h hours.

In total, the plumber earned $(150 + 75h)

A. On Tuesday, he completed 3 repair jobs and earned a total of more than $600. Thus

$150+75h>600$

B. Solve this inequality. Subtract 150:

$150+75h-150>600-150\\ \\75h>450$

Divide by 75:

$h>\dfrac{450}{75}\\ \\h>6$

This means, the plumber worked more than 6 hours.