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Gennadij [26K]
3 years ago
6

A line is represented by the equation y= 2/3x+1. What is the slope of the line with that equation

Mathematics
1 answer:
Gelneren [198K]3 years ago
7 0
X= -3/2 is the slope
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A right cylinder has a radius of 2 units and height of 5 units. What is the volume of the cylinder? Round to the nearest tenth.
Free_Kalibri [48]

Hi,

The volume of the cylinder is :

V = π × r^2 × h

V = 3,142 × (2)^2 × 5

V = 62, 8319 cm^3

π : Pi => 3,142

r : radius of the cylinder (2 units).

h : height of the cylinder (5 units).

The base of the cylinder is a circle , so to calculate the area we have to use the formula : area = π × r^2. And to find the volume , we have to multiply the area by the height.

•It was nice to help you, Bellalocc!

8 0
3 years ago
Select all ratios that are in their simplest form.<br> A 21:19 B 14:29 C 18:24 D 2:16 E 26:3
ludmilkaskok [199]

Answer:

pointss

Step-by-step explanation:

7 0
2 years ago
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A line has slope −34 and y–intercept 5. Which answer is the equation of the line? y=−5x+34 y=−34x+5 y=34x−5 y=5x−34?
Dafna1 [17]

The answer would be the first equation!!!!

3 0
3 years ago
Read 2 more answers
What are the solutions of the quadratic equation (x + 3)(x +3) = 49? Ax = -2 and x = -16 Bx = 2 and x = -10 Cx = 4 and x = -10 D
Ivahew [28]

Answer:

4 and -10

Step-by-step explanation:

\displaystyle (x + 3)(x +3) = 49 \\ x^2+3x+3x+9=49 \\ x^2 +6x+9=49 \\ x^2 + 6x + 9 - 49 = 0 \\x^2+6x-40=0 \\\\ \Delta=b^2-4ac \\ \Delta=6^2-4 \cdot 1 \cdot (-40) \\ \Delta=36+160 \\ \Delta=196 \\ \\ X_{1,2}=\frac{-b \pm \sqrt{\Delta} }{2a}  \\ \\ X_1=\frac{-b+\sqrt{\Delta} }{2a} = \frac{-6+14}{2} = \frac{8}{2}=4 \\ \\ X_2=\frac{-b-\sqrt{\Delta} }{2a}  = \frac{-6-14}{2}=\frac{-20}{2} = -10

4 0
3 years ago
Let g(x) = -5/?. Find g(g(-1))
IRISSAK [1]

Answer:

-1

Step-by-step explanation:

g(-1) = -5/-1 = 5

g(5) = -5/5

g(g(-1)) = -1

7 0
3 years ago
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