Answer:
12
Step-by-step explanation:
The question is missing some important details required to answer the question. I found a similar question, so I will answer using this details. If there is any differences in the details, you can still use my working by changing the value given:
Abdul will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $38 and costs an idditional $0.11 per mile driven. The second plan has an initial fee of $49 and costs an additional $0.07 per mile driven.
How many miles would Abdul need to drive for the two plans to cost the same?
Answer:
275 miles
Step-by-step explanation:
Let the distance travel be X
First plan:
Initial fee: 38
Per mile: 0.11
So the total cost is
C1 = 38 + 0.11X
Second plan:
Initial fee: 49
Per mile:0.07
So the total cost is
C2 = 49 + 0.07X
Since the question asked about when the total cost be the same, we can say that C1 = C2
C1 = C2
38 + 0.11X = 49 + 0.07X
0.11X - 0.07X = 49 - 38
0.04X = 11
X = 11/0.04 = 275
At 275 miles, the cost will be the same.
By the divergence theorem, the surface integral given by
(where the integral is computed over the entire boundary of the surface) is equivalent to the triple integral
where
is the volume of the region
bounded by
.
You have
![\implies \nabla\cdot\mathbf F=\dfrac{\partial}{\partial x}[x^2y]+\dfrac{\partial}{\partial y}[xy^2]+\dfrac{\partial}{\partial z}[4xyz]=8xy](https://tex.z-dn.net/?f=%5Cimplies%20%5Cnabla%5Ccdot%5Cmathbf%20F%3D%5Cdfrac%7B%5Cpartial%7D%7B%5Cpartial%20x%7D%5Bx%5E2y%5D%2B%5Cdfrac%7B%5Cpartial%7D%7B%5Cpartial%20y%7D%5Bxy%5E2%5D%2B%5Cdfrac%7B%5Cpartial%7D%7B%5Cpartial%20z%7D%5B4xyz%5D%3D8xy)
and so the integral reduces to
