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3 years ago

Please help me out with these

Mathematics

1 answer:

son4ous [18]3 years ago

3 0

First one-
9
2nd one-
the second page doesn't have a question
3rd one-
10.5
4th one-
10

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Plsss help me with this I will give brainiest

Cerrena [4.2K]

Answer:

3 + 3y is your answer!

Step-by-step explanation:

5 - 2 = 3

-7y + 10y = 3y

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3 years ago

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3. Determine whether a tangent line is shown in each diagram.

White raven [17]

The answer is A. Yes. 6^2 + 8^2 = 10^2

A tangent line usually extends out of the circle and intersects the circle at one point.

hope this helps !

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3 years ago

The total remodeling budget for Central Square Tower is 1.5×106 dollars. The owners of the building have set aside 6×105 dollars

DanielleElmas [232]

Answer:

40%

Step-by-step explanation:

assuming you actually mean 10^5 and 10^6, to find percentages you do

part/total x percent/100

you have (6x10^5/1.5x10^6) x (x/100)

cross multiply, and you have 6x10^7=1.5x10^6x

divide on both sides by 1.5x10^6

x=40

so the answer is 40%

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2 years ago

A sin^3theta+b cos^3theta=sintheta costheta and a sintheta-b costheta=0 then prove a^2+b^2=1

frozen [14]

Answer:

<em>Proof in explanation</em>

Step-by-step explanation:

<u>Trigonometric Identities</u>

The basic trigonometric identity is:

$\sin^2\theta+\cos^2\theta=1$

We'll use it and some basic algebra to prove that, given:

$a sin^3\theta+b cos^3\theta=sin\theta cos\theta$

And

$a\sin\theta-b\cos\theta=0$

Then

$a^2+b^2=1$

From the equation:

$a\sin\theta-b\cos\theta=0$

We have:

$a\sin\theta=b\cos\theta\qquad [1]$

The equation

$a sin^3\theta+b cos^3\theta=sin\theta cos\theta$

Can be rewritten as

$a\sin\theta \sin^2\theta+b \cos^3\theta=\sin\theta \cos\theta$

Replacing [1]:

$b\cos\theta \sin^2\theta+b \cos^3\theta=\sin\theta \cos\theta$

Taking the common factor:

$b\cos\theta (\sin^2\theta+ \cos^2\theta)=\sin\theta \cos\theta$

The expression in parentheses is 1, thus:

$b\cos\theta =\sin\theta \cos\theta$

Dividing by $\cos\theta$

$b=\sin\theta$

Replacing in

$a\sin\theta=b\cos\theta$

We have

$a\sin\theta=\sin\theta\cos\theta$

Dividing by $\sin\theta$

$a=\cos\theta$

Now:

$a^2+b^2=(\cos\theta)^2+(\sin\theta)^2$

This expression is 1, thus it's proven:

$\boxed{a^2+b^2=1}$

6 0

3 years ago

What is 5438268x8182728282

faust18 [17]

Answer:

44499869368695576 (4.44998693 x 10 to the 16th power) < Decimal version

Step-by-step explanation:

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3 years ago

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