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Sunny_sXe [5.5K]
3 years ago
9

In a math class there are 8 male students and 7 female students. A

Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer: 26.7%

Step-by-step explanation:

DanielleElmas [232]3 years ago
6 0

Answer:

Step-by-step explanation:

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SVETLANKA909090 [29]
The reciprocal is the flipped value so it will be11/9
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What is the probability against a spinner landing on a green section if the spinner had 15 sections and 3 of them are green ?
STatiana [176]
Fraction- 12/15
80% that it won't land on green
20%that it will land on green
(i wasn't sure what your ? was, so i put both choices.)
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x+4y=17 and -x-6y=-23 what's the x and y I really badly need this I need this so I can play at my basketball game tommorw and I
loris [4]

<u>Answer:</u>

  • x = 5
  • y = 3

<u>Solution:</u>

  • => x + 4y = 17

            -x - 6y = -23

  • => -2y = -6
  • => y = 3

<u>Now, let's substitute the value of y into the first equation.</u>

  • x + 4y = 17
  • => x + 4(3) = 17
  • => x + 12 = 17
  • => x = 5

<u>Let's check our answer to make sure it is correct.</u>

<u>Check:</u>

  • -x - 6y = -23
  • => -(5) - 6(3) = -23
  • => -5 - 18 = -23
  • => -23 = -23

Hence, this is proven correct.

Hoped this helped.

BrainiacUser1357

7 0
2 years ago
I need help ASAP <br> Integrated math II
Molodets [167]

Answer:

\boxed{ \bold{ \sf{x = 16}}}

\boxed{ \bold{ \sf{m < AFD = 82}}}

Step-by-step explanation:

\sf{5x + 18 = 3x + 50}

( Being vertically opposite angles)

Vertically opposite angles are always equal.

Move variable to L.H.S and change it's sign

Similarly, Move constant to R.H.S and change it's sign

⇒\sf{5x  - 3x = 50 - 18}

Collect like terms

⇒\sf{2x = 50 - 18}

Subtract 18 from 50

⇒\sf{2x = 32}

Divide both sides of the equation by 2

⇒\sf{ \frac{2x}{2}  =  \frac{32}{2} }

Calculate

⇒\sf{x = 16}

The value of x is 16

Now, let's find value of m<AFD :

\sf{m < afd + 5x + 18 = 180} ( sum of angle in straight line )

plug the value of x

⇒\sf{m < AFD + 5 \times 16 + 18 = 180}

Multiply the numbers

⇒\sf{m < AFD + 80 + 18 = 180}

Add the numbers

⇒\sf{m < AFD + 98 = 180}

Move constant to R.H.S and change it's sign

⇒\sf{m < AFD = 180 - 98}

Subtract 98 from 180

⇒\sf{m < AFD = 82}

Value of m<AFD = 82

Hope I helped!

Best regards!!

3 0
3 years ago
Please help me with this question, and show the work . Thank you so much !!!!
jenyasd209 [6]
Step 1 is wrong it should be: 2x - 3x - 1=3
6 0
3 years ago
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