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Sunny_sXe [5.5K]
3 years ago
9

In a math class there are 8 male students and 7 female students. A

Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer: 26.7%

Step-by-step explanation:

DanielleElmas [232]3 years ago
6 0

Answer:

Step-by-step explanation:

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Check my answer please?
grandymaker [24]
Yes you are right it's C
4 0
3 years ago
yuko is volunteering at the food bank. He is creating thanksgiving food baskets to give to local families. He has 192 cornbread
Deffense [45]

Answer:

  • 32 baskets
  • 2 boxes of stuffing mix, 3 cans of vegetables, 6 cornbread muffins

Step-by-step explanation:

The greatest common factor (GCF) will be the greatest number of baskets yuko can create. We can examine the factoring of these numbers to see what it might be.

  64 = 2^6

  96 = 2^5 × 3

  192 = 2^6 × 3

The unique factors are 2 and 3, and the lowest powers of each are 5 and 0, respectively. Then the GCF is ...

  2^5 × 3^0 = 32 × 1 = 32

After the factor of 32 is removed from each of these numbers, we have ...

  64 = 32·2    boxes of stuffing mix

  96 = 32·3    cans of vegetables

  192 = 32·6   cornbread muffins

These other factors are the numbers of the corresponding item that will be in each of the 32 baskets:

  • 2 boxes of stuffing mix
  • 3 cans of vegetables
  • 6 cornbread muffins
6 0
3 years ago
What is the coefficient of x2y3 in the expansion of (2x + y)5?
Zigmanuir [339]

Option C:

The coefficient of x^{2} y^{3} is 40.

Solution:

Given expression:

(2 x+y)^{5}

Using binomial theorem:

(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}

Here a=2 x, b=y

Substitute in the binomial formula, we get

(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}

                                                            $+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}

Let us solve the term one by one.

$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}

$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y

$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}

$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}

$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}

$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}

Substitute these into the above expansion.

(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}

The coefficient of x^{2} y^{3} is 40.

Option C is the correct answer.

5 0
2 years ago
A card is picked at random from the following set. ​ ​What is P(9) ? Write your answer as a percentage in the box given below.
irina1246 [14]

Answer:

25%

Step-by-step explanation:

The (not mentioned in the question) set is: 6 7 8 9.

There are 4 total outcomes and only 1 favorable outcome, then the probability to pick a 9 is:

P(9) = favorable outcome/total outcomes

P(9) = 1/4 = 0.25 or 0.25*100 = 25%

4 0
3 years ago
A North Face Jacket costs $65. It is on sale for 20% off. What is the amount of discount?
sineoko [7]
The answer should be $13 !! hope that helps
5 0
2 years ago
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