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4 years ago

Which risk management framework does the organization of standardization publish

Computers and Technology

1 answer:

olga2289 [7]4 years ago

3 0

Answer:

ISO 31000:2009 publishes principles and generic guidelines on risk management.

Explanation:

ISO 31000:2009 can be applied to any public, private or community company, organization, society or individual. Hence, ISO 31000:2009 is not particular to either business or area.

ISO 31000:2009 can be implemented during the period of an industry and to a broad variety of actions, including policies and judgments, guidance, methods, functions, plans, goods, services, and assets.

ISO 31000:2009 can be implemented to any type of danger, whatever its kind, whether possessing positive or negative outgrowths.

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True or False

sineoko [7]

Answer:

VPNs encrypt your traffic while proxy servers don't.

Explanation:

8 0

3 years ago

What is referred to by the phrase “Web 2.0”?

Tresset [83]

Answer:

Web 2.0

the second stage of development of the World Wide Web, characterized especially by the change from static web pages to dynamic or user-generated content and the growth of social media.

Explanation:

It refers to websites that emphasizes user-generated content, ease of use, compatible with other products, systems, and devices for end users.

4 0

3 years ago

def getCharacterForward(char, key): """ Given a character char, and an integer key, the function shifts char forward `key` steps

zhenek [66]

Answer:

def getCharacterForward(char, key):
charList = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
if(len(char) > 1):
return None
elif(not isinstance(key, int)):
return -1
else:
index = charList.find(char)
if(index + key <= 25):
return charList[index + key]
else:
return charList[(index + key)% 26]
print(getCharacterForward("C", 4))
print(getCharacterForward("X", 4))

Explanation:

Firstly, define a charList that includes all uppercase alphabets (Line 2). We presume this program will only handle uppercase characters.

Follow the question requirement and define necessary input validation such as checking if the char is a single character (Line 4). We can do the validation by checking if the length of the char is more than 1, if so, this is not a single character and should return None (Line 5). Next, validate the key by using isinstance function to see if this is an integer. If this is not an integer return -1 (Line 6 - 7).

Otherwise, the program will proceed to find the index of char in the charList using find method (Line 9). Next, we can add the key to index and use the result value to get forwarded character from the charList and return it as output (Line 11).

However, we need to deal a situation that the char is found at close end of the charList and the forward key steps will be out of range of alphabet list. For example the char is X and the key is 4, the four steps forward will result in out of range error. To handle this situation, we can move the last two forward steps from the starting point of the charList. So X move forward 4 will become B. We can implement this logic by having index + key modulus by 26 (Line 13).

We can test the function will passing two sample set of arguments (Line 15 - 16) and we shall get the output as follows:

8 0

3 years ago

Use the YEARFRAC function to work out how many years difference is there between the date 1980-07-31 (31 July 1980) and 1998-05-

zhenek [66]

Answer: 17.7 Years

Explanation:

YEARFRAC is a function in Microsoft Excel that returns the year fraction representing the number of whole days between a particular start date and an end date.

A typical view of the function is:

=YEARFRAC(start_date, end_date, [basis])

All that needs to be done is

1. Type in the equal to sign(=) in the cell you want your answer,

2. Type in YEARFRAC and open your bracket,

3. Input your start date and end date, close your bracket and press enter.

6 0

3 years ago

Create a report showing the Order ID, the name of the company that placed the order, and the first and last name of the associat

8090 [49]

Answer:

/******************************

Both of the queries below will work in SQL Server

Oracle

******************************/

SELECT o.OrderID, c.CompanyName, e.FirstName, e.LastName

FROM Orders o

JOIN Employees e ON (e.EmployeeID = o.EmployeeID)

JOIN Customers c ON (c.CustomerID = o.CustomerID)

WHERE o.ShippedDate > o.RequiredDate AND o.OrderDate > '1-Jan-1998'

ORDER BY c.CompanyName;

/******************************

MySQL

******************************/

SELECT o.OrderID, c.CompanyName, e.FirstName, e.LastName

FROM Orders o

JOIN Employees e ON (e.EmployeeID = o.EmployeeID)

JOIN Customers c ON (c.CustomerID = o.CustomerID)

WHERE o.ShippedDate > o.RequiredDate AND o.OrderDate > '1998-01-01'

ORDER BY c.CompanyName;

8 0

3 years ago