Hi,
the program is as follows
___________________________________________________________
import java.io.*;
class doubleval
{
public static void main()throws IOException
{
DataInputStream dt=new DataInputStream(System.in);
System.out.println("Enter NUMBER WHOSE DOUBLE U WANT TO PRINT");
int n=Integer.parseInt(dt.readLine());
for(int i=n;i<=100;i=2*i)
{
System.out.println(i);
}
}
}
JAVA programming was employed...
What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules
Solution:
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x1[i][j] = num.nextInt();
}
}// End of Array 1, x1.
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x2[i][j] = num.nextInt();
}
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:
x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
x1rules = true;
system.out.print(x1rules);
}
else
{
system.out.print(x1rules);
}//Conditional Statement
It may be D) because it is actually a simplified version of Google maps.
