Answer:
R V
1 9π in³
2 36π in³
3 81π in³
Step-by-step explanation:
For, r = 1
V = π(1)²9 = 9π in³
For, r = 2
V = π(2)²9 = 4*9π in³ = 36π in³
For r = 3
V = π(3)²9 = 9*9π in³ = 81π in
R V
1 9π in³
2 36π in³
3 81π in³
Answer:
Add the numbers together and divide by the number of numbers. (The sum of values divided by the number of values). Arrange the numbers in order, find the middle number. (The middle value when the values are ranked).
Answer:
<h2>A = 20</h2><h2>P = 6√10</h2>
Step-by-step explanation:
The formula of a distance between two points:

A(-3, 0) , B(3, 2)

A(-3, 0), D(-2, -3)

AB = CD and AD = BC
The area of a rectangle:

Substitute:

The perimeter of a rectangle:

Substitute:

Answer:
Here,
length = 8m
height = 4m
4s = 15 per m^2
Now,
300 per meter = 300 * 15 per m^2
= 4500 per m^2