Sequence number fill in the blanks: 2, ?, ?, ?, ?, 21

En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand

Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

$\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}$ (1)

Donde:

$F_{1}$ - Fuerza experimentada por el elefante, medida en newtons.

$F_{2}$ - Fuerza aplicada sobre el plato pequeño, medida en newtons.

$A_{1}$ - Área del plato grande, medida en metros cuadrados.

$A_{2}$ - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

$F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}$

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

$F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g$ (2)

Donde:

$D_{1}$ - Diámetro del plato grande, medido en centímetros.

$D_{2}$ - Diámetro del plato pequeño, medido en centímetros.

$m$ - Masa del elefante, medida en kilogramos.

$g$ - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que $D_{1} = 0.75\,m$ , $D_{2} = 0.13\,m$ , $m = 2900\,kg$ y $g = 9.807\,\frac{m}{s^{2}}$ , entonces la fuerza a aplicar al émbolo pequeño es:

$F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$F_{2} = 854.473\,N$

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

3 0

3 years ago

Which term completes the product so that it is the difference of squares?

Leokris [45]

Answer:

3

Step-by-step explanation:

Note the general factorisation of a difference of 2 squares is

a² - b² = (a + b)(a + b)

Given

(- 5x - 3)(- 5x + ?)

Then ? = 3 so that the complete factors are

(- 5x - 3)(- 5x + 3)

7 0

3 years ago

Read 2 more answers

Select all polynomials that are divisible by (x-1).

goldenfox [79]

Answer:

The answer to your question is below

Step-by-step explanation:

*A(x)=3x³ + 2x² - x This polynomial is not divisible by (x - 1)

Factor completely 3x(x + 1)(3x - 1)

*B(x)=5x³ - 4x² - x This polynomial is divisible by (x - 1)

factor completely 3x(x - 1)(5x + 1)

*C(x)=2x³ - 3x² + 2x - 1 This polynomial is divisible by (x - 1)

Synthetic division 2 - 3 + 2 -1 1

2 -1 1

2 -1 1 0

*D(x)=x³ + 2x² + 3x + 2 This polynomial is not divisible by (x - 1)

Synthetic division 1 2 3 2 1

1 3 6

1 3 6 8

3 0

4 years ago

Callie has a new kitten. They can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18

gavmur [86]

Answer:

The weight of cat is 14 pounds and the weight of kitten is 4 pounds.

Step-by-step explanation:

Given:

Callie has a new kitten. It can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18 pounds.

Now, to find the weight of each animal:

Let the cat's weight be $x.$

And the kitten weight = $\frac{x}{2} -3$

Total weight of cat and kitten = 18 pounds.

Now, to set an equation to get the weight of each animal:

$(x)+(\frac{x}{2}-3)=18$

$x+\frac{x}{2} -3=18$

$\frac{2x+x-6}{2} =18$

$\frac{3x-6}{2} =18$

Multiplying both sides by 2 we get:

$3x-6=36$

Adding both sides by 6 we get:

$3x=42$

Dividing both sides by 3 we get:

$x=14\ pounds.$

The weight of cat = 14 pounds.

Substituting the value of $x$ to get the kitten's weight:

$\frac{x}{2} -3\\\\=\frac{14}{2}-3\\\\=7-3\\\\=4.$

The kitten's weight = 4 pounds.

Therefore, the weight of cat is 14 pounds and the weight of kitten is 4 pounds.

7 0

3 years ago

Write the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5).

lys-0071 [83]

Answer:

$(x+1)^2 + (y- 3.5)^2 =64$

Step-by-step explanation:

We are given that endpoints of a diameter at the points (7,2) and (-9,5).

Center of the circle is the mid point of diameter

So, first find the mid point of diameter

Formula : $x=\frac{x_1+x_2}{2} , y=\frac{y_1+y_2}{2}$

$(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)$

Substitute the values in formula

$x=\frac{7-9}{2} , y=\frac{2+5}{2}$

$x=-1 , y=3.5$

So, center of circle = (h,k )=(-1,3.5)

To find length of diameter :

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)$

$d=\sqrt{(-9-7)^2+(5-2)^2}$

$d=\sqrt{265}$

Length of radius = r = $\frac{Diameter}{2}=\frac{\sqrt{256}}{2}$

Standard form of the equation of the circle : $(x -h)^2 + (y- k)^2 = r^2$

(h,k )=(-1,3.5)

$r=\frac{\sqrt{256}}{2}$

Equation of the circle : $(x+1)^2 + (y- 3.5)^2 =(\frac{\sqrt{256}}{2})^2$

Equation of the circle : $(x+1)^2 + (y- 3.5)^2 =64$

Hence the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5) is $(x+1)^2 + (y- 3.5)^2 =64$

5 0

4 years ago