Answer:
Step-by-stegridp explanation:
Answer:
1) 24
2) 21/2 = 10 1/2
3) 2/5
Step-by-step explanation:
1) We have 2 2/3 * 9, to solve this we have to know that in multiplications we multiply the numerator from the first fraction times the numerator from the second fraction, and the denominators are multiplied too.
We also know that 2 2/3 = 8/3, because we multiply 2 times the denominator and then we add that result plus the numerator.
So now we have:
8/3 * 9 = 72/3 = 24
2) We do the same thing than in problem 1.
We have -4 1/2 * -2 1/3, so first we change them:
-4 1/2 = -9/2 and -2 1/3 = -7/3, so we have:
-9/2 * -7/3 = 63/6 = 21/2 = 10 1/2
3) We have 1/3 ÷ 5/6, to divide we can flip the second fraction and just solve it as a multiplication:
1/3 * 6/5 = 6/15 = 2/5
<span>So we want to know the difference between a= 126 1/4 and b= 78 2/3. Lets turn them into a fraction: a = 124*4 + 1/4 = 496/4 + 1/4 = 495/4. b= 78*3 + 2/3 = 234/3 + 2/3 = 236/3. Now we find the common denominator of a and b: and that is 12. so lets multiply a by 3/3 and b by 4/4: (495/4)*(3/3)=1485/12. (236/3)*(4/4)=944/12. Now the difference is: 1485/12 - 944/12=541/12 and that is: 45 1/12 </span>
Answer:
The length of side x is ![x = \sqrt{6}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B6%7D)
Step-by-step explanation:
Pythagorean Theorem:
In a right triangle, with sides a and b, and hypothenuse h, we have that:
![a^2 + b^2 = h^2](https://tex.z-dn.net/?f=a%5E2%20%2B%20b%5E2%20%3D%20h%5E2)
In this question:
The vertical line on the sides means that both are equal, that is, measuring x, so
.
Hypothenuse is the square root of 12. So ![h = \sqrt{12}](https://tex.z-dn.net/?f=h%20%3D%20%5Csqrt%7B12%7D)
![x^2 + x^2 = (\sqrt{12})^2](https://tex.z-dn.net/?f=x%5E2%20%2B%20x%5E2%20%3D%20%28%5Csqrt%7B12%7D%29%5E2)
![2x^2 = 12](https://tex.z-dn.net/?f=2x%5E2%20%3D%2012)
![x^2 = \frac{12}{2}](https://tex.z-dn.net/?f=x%5E2%20%3D%20%5Cfrac%7B12%7D%7B2%7D)
![x^2 = 6](https://tex.z-dn.net/?f=x%5E2%20%3D%206)
![x = \sqrt{6}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B6%7D)
The length of side x is ![x = \sqrt{6}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B6%7D)
58 is 50 plus 8. So its 50 and 8.That is for the first one.