The Pythagorean theorem computed shows that the length of the guy wire, to the nearest foot, is 207 ft.
<h3>How to solve the length?</h3>
Here, we have two similar right triangles, ΔABE and ΔCDE.
CD = 11 ft
DE = 2 ft
BD = 35 ft
First, find AB:
AB/11 = (35 + 2)/2
AB/11 = 37/2
Cross multiply
AB = (37 × 11)/2
AB = 203.5 ft
Then, apply Pythagorean Theorem to find AE:
AE = √(AB² + BE²)
AE = √(203.5² + 37²)
AE = 207 ft
Therefore, the length of the guy wire is 207 ft.
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Since you haven't identified this figure, I'm going to assume that it's a rectangle.
The Perimeter of a rectangle of length L and width W is P = 2L + 2W.
Here you are given the Perimeter and the length, and are to find the width, W.
Solving the above equation for W, we get P - 2L = 2W.
Dividing by 2 (to isolate that W), we get
P
-- - L = W
2
Substitute P= 6 yds and L = 6 feet (or 2 yds), find W (in yards).
The 2 angles are alternate angles so they are equal:-
3x + 4 = 115
3x = 115-4 = 111
x = 37 answer
