Answer:
226pi
Step-by-step explanation:
2 * pi * 7 *(7+12)
X²(x - 4) +4 (x - 4)
(x² + 4) (x - 4)
First find the common terms that can enter into both x³ and 4x² then write its down in this case it’s x² that can enter x³ leaving only x _since x³/x² = subtract of the indices. x² will also enter 4x² leaving only four hence you having x² (x - 4)
then do the same for the next pair of terms giving you 4 that can enter into both 4 and 16
Leaving you with +4 (x - 4)
Now you can put the common terms together like so (x² + 4) and choose get one of the other two which are the same= (x - 4)
= (x² + 4) (x - 4)
Answer: Hello your question is incomplete below is the missing part
Which of the following statements about Hannah’s claim is supported by the interval?
A) Hannah is likely to be incorrect because the difference in the sample means was 18.6−14.4=4.218.6−14.4=4.2 hours.
B) Hannah is likely to be incorrect because 9 is not contained in the interval.
C)The probability that Hannah is correct is 0.99 because 9 is not contained in the interval.
D)The probability that Hannah is correct is 0.01 because 9 is not contained in the interval.
E)Hannah is likely to be correct because the difference in the sample means (18.6−14.4=4.2)(18.6−14.4=4.2) is contained in the interval.
Answer : Hannah is likely to be incorrect because 9 is not contained in the interval. ( B )
Step-by-step explanation:
The statement that is supported by the interval in Hannah's claim is that
Hannah is likely to be incorrect because 9 is not contained in the interval.
Answer: 121 mph
Step-by-step explanation: First, I did 6 x 7, and I got 42. Then I did 42 + 79, and I got 121 mph as my answer.
Answer:
- sin(4a) = -24/25
- cos(4a) = 7/25
Step-by-step explanation:
Your calculator can tell you these values:
sin(4a) = sin(4·arctan(3)) = -0.96 = -24/25
cos(4a) = cos(4·arctan(3)) = 0.28 = 7/25
_____
Some useful trig identities are ...
sin(2a) = 2tan(a)/(1 +tan(a)^2)
cos(2a) = (1 -tan(a)^2)/(1 +tan(a)^2)
Filling in the given value for tan(a), we find ...
sin(2a) = 2(3)/(1+3^2) = 6/10 = 3/5
cos(2a) = (1 -3^2)/(1 +3^2) = -8/10 = -4/5
Now, double-angle formulas are useful:
sin(4a) = 2sin(2a)cos(2a) = 2(3/5)(-4/5) = -24/25
cos(4a) = 1 -2sin(2a)^2 = 1 -2(3/5)^2 = 7/25
The desired trig function values are sin(4a) = -24/25; cos(4a) = 7/25.
