A car travels 32 km due north and
1 answer:
Answer:
Ifa,bandcare the
sides opposite to anglesA,B,&C.
By Cosine Rule,
b
2
=32
2
+46
2
−(2×32×46cos140°)
b
2
=1024+2116−2944cos140°
b
2
=3140−2944cos140°
b
2
=3140+2255.234841
b
2
=5395.234841
b=73.45
By Sine Rule,
sinC
32
=
sin140°
73.45
sinC=
73.45
32sin140°
sinC=0.2800
C=16.26°
The direction of the resultant
vector is measured from0°east
to the resultant, this angle isθ−90°,
90°is the total angle in
the first quadrant.
∴θ−90°=C+ϕ
ϕ=50°{Alternate angles are equal}
∴The direction of the car’s
resultant vector is50°+16.26°=66.26°south of east
Step-by-step explanation:
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