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3 years ago

6

9^3x-7=9^5-x what is the answer

2 answers:

xxMikexx [17]3 years ago

7 0

Ok, so if $a^m=a^n$ where a=a, then assume that m=n
so

$9^{3x-7}=9^{5-x}$ , 9=9, so 3x-7=5-x

3x-7=5-x
add x to both sides
4x-7=5
add 7 to both sides
4x=12
divide both sides by 4
x=3

lukranit [14]3 years ago

6 0

We can take the 9's out and get
3x-7=5-x
4x=12
x=3

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Step-by-step explanation:

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Step-by-step explanation:

This question requires an attachment.

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