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denis23 [38]
3 years ago
6

9^3x-7=9^5-x what is the answer

Mathematics
2 answers:
xxMikexx [17]3 years ago
7 0
Ok, so if a^m=a^n where a=a, then assume that m=n
so

9^{3x-7}=9^{5-x}, 9=9, so 3x-7=5-x

3x-7=5-x
add x to both sides
4x-7=5
add 7 to both sides
4x=12
divide both sides by 4
x=3
lukranit [14]3 years ago
6 0
We can take the 9's out and get
3x-7=5-x
4x=12
x=3



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