This is a matter of Amount = Rate times time.
First, find the area of the circular opening. A = pi (r^2). Here,
A = pi(10.5 inches)^2.
To obtain the volume of water that flows out of the pipe per second, multiply this area by the 30 inches per second rate.
That comes out to a volume per second of Volume rate = pi*(10.5 inches)^2 * 30 inches per second:
Volume rate = 3.14(110.25 in^2)(30 inches/sec)
= 10390.8 cubic inches per second
Convert this result to cubic feet per second. Recall that 1 cubic foot = (12 inches)^3, or 1728 cubic inches / 1 cubic foot.
Thus, 10390.8 cubic inches per second comes out to
10390.8 cubic inches
---------------------------- = Just over 6 cubic feet per sec.
1728 cu. inches
---------------------
1 cu. ft
How many sec in 1 day? 1 day = 24 hours
1 hour = 60 minutes
60 seconds = 1 minute
Figure out how many seconds there are in 1 day, and then multiply your result by 6 cu. ft. / sec.
Answer:
20%
Step-by-step explanation:
8⁄40 = ⅕ = 20%
The Greatest Common Factor [GCF] is 8, both denominator and numerator by 8, to get ⅕, which is 20% [0,2 - twice to the right → 20% (attach the percentage symbol)].
I am joyous to assist you anytime.
<span>A refrigerator contains 6 apples, 5 oranges, 10 bananas, 3 pears, 7 peaches, 11 plums, and 2 mangos. Imagine you stick your hand into the refrigerator and pull out a piece of fruit at random. What is the sample space for this process? a. S = {apple, orange, banana, pear, peach, plum, mango} b. S = {6, 5, 10, 3, 7, 11, 2} c. S = {6 apples, 5 oranges, 10 bananas, 3 pears, 7 peaches, 11 plums, 2 mangos}</span>
See the pic for the answer. You just multiply each term on the left by each term on the top. The coefficient is just the number in front of an unknown.
Answer:
Option D.
Step-by-step explanation:
We can easily solve this problem by using a graphing calculator or plotting tool.
The function is
f(t) = a*sin (b*t +c) + d
Please, see attached picture below.
By looking at the picture with all the possible cases, we can tell that the correct option is D.
The function has a period of T = 6π
Max . Amplitude = 9
Min . Amplitude = -5
