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d1i1m1o1n [39]
3 years ago
14

Using known taylor series, find the first four nonzero terms of the taylor series about 0 for the function. sqrt((1 + t))sin(t)

Mathematics
2 answers:
grigory [225]3 years ago
4 0

Answer:

T series

Step-by-step explanation:

Tcecarenko [31]3 years ago
3 0

x +  \frac{ {x}^{2} }{2}   -  \frac{ 7{x}^{3} }{24}  -  \frac{ {x}^{4} }{48}
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Can I have the answer step by step
iren2701 [21]
The equation you’re using here would be:
1300(1.04)^x.

After 3 years, you’d plug in 3 for the value of x.

The amount of money in the bank after 3 years would be $1,462.32.




3 0
4 years ago
Write the equation of the line that passes through the given points<br> (0,2)) and (-9, -3)
Irina18 [472]

Step-by-step explanation:

Y= m x+ C

m (slope ) = 2 - (_3) / 0 _( - 9 )

= 5 / 9

( O, 2 ) Satisfying equation

2= 5/9 ( 0) + C

C= 2

So eq. is

y= 5/ 9 X + 2

7 0
3 years ago
A tent is in the shape of a triangular pyramid with a square footprint (base). the tent is 6 feet high and has a volume of 128 c
sergiy2304 [10]
You can solve for the base by inputting all the values you know into the volume formula for a triangular pyramid, which is:

(1/3)bh = V    

where b = base and h = height.

(1/3)b(6) = 128
2b = 128
b = 64 feet.

hope that helps!! if you liked this answer please rate it as brainliest so I can gain the next rank!! thank you!!!!


8 0
4 years ago
Please help me answer one of these!
babunello [35]

This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


4. ... construct the perpendicular bisector ... a different way?


Maybe what I first described is different; there are no parallel lines.



8 0
4 years ago
Consider this data set.
trapecia [35]

Answer:

3 and 34

Step-by-step explanation:

they are the extremes in this, you want to look for out of place numbers when dealing with outliers

8 0
3 years ago
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