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3 years ago

Please help !!! Picture shown

Mathematics

2 answers:

Alenkinab [10]3 years ago

7 0

Your Answer would be D or 1/9
H0P3 It H3LPS :)

WITCHER [35]3 years ago

3 0

I think it's D. Hope it helps good luck

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6x+1=8x-9<br><br> pls help i forgot how to do dis yall

Nata [24]

Answer:

6x+1=8x-9

6x=8x-9-1

6x=8x-8

6 0

2 years ago

Read 2 more answers

Use the product of powers property to simplify the numeric expression.

motikmotik

Answer:

The value of $4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}$ is $4^{\dfrac{8}{15}}$ .

Step-by-step explanation:

We need to simplify the numeric expression using property. The expression is as follows :

$4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}$

The property to be used is : $x^a{\cdot} x^b=x^{a+b}$

This property is valid if the base is same. Here, base is x.

In this given problem, x = 4, a = 1/3 and b = 1/5

So,

$4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}}=4^{\dfrac{1}{3}+\dfrac{1}{5}}\\\\=4^{\dfrac{5+3}{15}}\\\\=4^{\dfrac{8}{15}}$

So, the value of $4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}$ is $4^{\dfrac{8}{15}}$ .

8 0

4 years ago

Cindy dissolves 19 1 /4 grams of drink mix in 1 3 /4 ounces of water. What is the unit rate in grams of drink mix per ounce of w

Korolek [52]

Answer:

Unit rate in grams of drink mix per ounce of water = 11 gram / ounces

Step-by-step explanation:

Given:

Amount of drink mix = 19 (1 /4) gram = 19.25 gram

Amount of water = 1 (3 /4) ounces = 1.75 ounces

Find:

Unit rate in grams of drink mix per ounce of water = ?

Computation:

⇒ Unit rate in grams of drink mix per ounce of water = Amount of drink mix / Amount of water

⇒ Unit rate in grams of drink mix per ounce of water = 19.25 / 1.75

⇒ Unit rate in grams of drink mix per ounce of water = 11 gram / ounces

5 0

3 years ago

PLEASE help me with this question! No nonsense answers and answer with full solutions please!

ohaa [14]

Answer: b) {-3, 0.5}

Step-by-step explanation:

The new equation is the original equation plus 6. Move the original graph UP 6 units. The solutions are where it crosses the x-axis.

$\text{Original equation:}\quad f(x)=\dfrac{15}{x}-\dfrac{9}{x^2}\\\\\\\text{New equation:}\quad\dfrac{15}{x}+6=\dfrac{9}{x^2}\\\\\\.\qquad \qquad f(x)= \dfrac{15}{x}-\dfrac{9}{x^2}+6$

+6 means it is a transformation UP 6 units.

Solutions are where it crosses the x-axis.

The curve now crosses the x-axis at x = -3 and x = 0.5.

4 0

3 years ago

Can someone please help

Andrews [41]

Answer:

5 $\sqrt{6}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Given

$\sqrt{150}$

= $\sqrt{25(6)}$

= $\sqrt{25}$ × $\sqrt{6}$

= 5 $\sqrt{6}$

3 0

3 years ago