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3 years ago

12

PLEASE HELP I ONLY HAVE 10 MINS!!

1 answer:

lbvjy [14]3 years ago

6 0

The answer to both equations is 'A'. For the first you just input the value of 20 to replace n and get 700. (Side-note: the number 20, which is your variable, should be nowhere in the function so you know b is wrong). so now that you have your answer 700 the second part is self explanatory.

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I got 2 questions.

alexandr402 [8]

Answer:

1. In triangle ABC,

AC = a = 10, BC =b= 7 and ∠ C = 90°

By cosine law,

$AB^2 = 7^2 + 10^2 - 2\times 7\times 10 cos 90^{\circ}$

$AB^2 = 49 + 100 - 0$

$AB^2 = 149$

$AB= \sqrt{149}$

Now, by the law of sine,

$\frac{sin B}{10} = \frac{sin90^{\circ}}{\sqrt{149} }$

$sin B = \frac{10}{\sqrt{149} }$

$\angle B = 55.0079798014\approx 55.008^{\circ}$

2. In triangle ABC,

∠B = 30°, AB=c=10 and ∠C = 90°

∠A = 180°-(30+90)°=60°

$\frac{AC}{10}=sin30^{\circ}$

⇒ $AC = \frac{10}{2} = 5$

By Pythagoras,

$CB^2 = AB^2 - AC^2=10^2 - 5^2 = 100 - 25 = 75$

⇒ $CB = \sqrt{75} =8.66025403784\approx 8.66$

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