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4 years ago

In a classroom, the average weight of 20 students is 148 pounds.

Mathematics

1 answer:

SVEN [57.7K]4 years ago

3 0

The answer is h 142 your welcome

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Find the midpoint of (0, 4) and (2, -2)

lidiya [134]

Answer:

$\text{Midpoint} = (1, \; 1)$

Step-by-step explanation:

$M = (x_M, \; y_M)$

$M = \left(\dfrac{x_1 + x_2}{2}, \; \dfrac{y_1 + y_2}{2}\right)$

$M = \left(\dfrac{0 + 2}{2}, \; \dfrac{4 + -2}{2}\right)$

$M = \left(\dfrac{2}{2}, \; \dfrac{2}{2}\right)$

$M = (1, \; 1)$

5 0

2 years ago

Read 2 more answers

Find the missing value so that the line passing through the points has the given slope.

galben [10]

Answer:

Step-by-step explanation:

4-1=3/11-7=4

7 0

3 years ago

Given: m

Nutka1998 [239]

Answer:

$m\angle MEJ=25^{\circ}.$

Step-by-step explanation:

The arcs LY, KM, KL and MJ together form the full revolution angle, thus

$4x+50^{\circ}+6x+x+10^{\circ}+4x=360^{\circ},\\ \\15x=300^{\circ},\\ \\x=20^{\circ}.$

Note that

$m\angle MOJ=4x=80^{\circ},$

then

$m\angle MLJ=\dfrac{1}{2}\cdot 80^{\circ}=40^{\circ}.$

So,

$m\angle ELM=180^{\circ}-40^{\circ}=140^{\circ}.$

Also

$m\angle LOK=30^{\circ},$

$m\angle KML=\dfrac{1}{2}\cdot 30^{\circ}=15^{\circ}.$

In triangle EML,

$m\angle MEL+m\angle EML+m\angle ELM=180^{\circ},\\ \\m\angle MEL=180^{\circ}-15^{\circ}-140^{\circ}=25^{\circ}.$

Thus, $m\angle MEJ=25^{\circ}.$

7 0

4 years ago

Find the value of x.<br><br> 3x + 45 = 90

seropon [69]

3x + 45 = 90
3x = 90 - 45
3x = 45
x = 45/3
x = 15

8 0

3 years ago

What is the answer to 25/5(2*3)

SVEN [57.7K]

According to P E M D A S (parentheses, exponents, multiplication, division, addition, and subtraction) (2*3)=(6) and 25/5 is 5. 5(6)=30. Your answer is 30.

5 0

4 years ago