In a classroom, the average weight of 20 students is 148 pounds.

HELP DUE IN 15 MINS!

boyakko [2]

Answer:

r = $2\sqrt{5}$

$(x - 3)^{2} + ( y - 2)^{2} = 20$

Is this a live test question or a homework question?

Step-by-step explanation:

the radius is the distance between (3, 2) and (5, -2)

$r^{2}$ = ${(3 - 5)^{2} + (2 + 2)^{2} }$

= $(-2)^{2} + 4^{2}$

= 4 + 16 = 20

r = $\sqrt{20 } = 2\sqrt{5}$

Equation of circle: $(x - 3)^{2} + ( y - 2)^{2} = 20$

8 0

2 years ago

Read 2 more answers

Question 12 (1 point)

Mademuasel [1]

Answer:

B) Variable Expense

Step-by-step explanation:

Because you choose to have a pet.

3 0

2 years ago

Can someone help me ?

Alex Ar [27]

All you need to do is divide 2.25 by 2!

The answer is 1.125!

I hope this helps! :)

5 0

2 years ago

Mr. Harris is packaging items to give to his students. He has 48 pencils and 30 notebooks. He wants each package to contain the

guapka [62]

Answer:

The maximum number of packages that can be made with each package have same number of each item is = 6

Step-by-step explanation:

Given:

Mr. Harris has 48 pencils and 30 notebooks.

To find the number of packages he can make with each package have same number of each item.

Solution:

Number of pencils = 48

Number of notebooks = 30

In order to find the number of packages he can make with each package have same number of each item, we will find the greatest common factor of the given numbers.

To find the G.C.F., we will list down the prime factors of each.

$48=2\times 2\times 2\times 2\times 3$

$30=2\times 3\times 5$

We find that the G.C.F. = $2\times 3$ = 6

Thus, the maximum number of packages that can be made with each package have same number of each item is = 6

4 0

2 years ago

Answer the following 3 question(s) using the information from the scenario below.

finlep [7]

Answer:

Answer 1: a. Moonlight: C=75n+1000

Riverside: C=50n+1500

Answer 2: c. The solution coordinates are c. (20, 2500)

Answer 3: c. When there are 20 guests attending the price is $2500.

Step-by-step explanation:

Moonlight Hall:

Fixed cost = $1000

Cost per guest = $75

Cost of 'n' guests = 75 $\times n$

Total cost of moonlight hall = Fixed cost + Cost of 'n' guests

$\Rightarrow 1000 + 75 \times n$

Riverside Hall:

Fixed cost = $1500

Cost per guest = $50

Cost of 'n' guests = 50 $\times n$

Total cost of moonlight hall = Fixed cost + Cost of 'n' guests

$\Rightarrow 1500 + 50 \times n$

Hence, Answer 1:

a. Moonlight: C=75n+1000

Riverside: C=50n+1500

Answer 2: Coordinates of solution:

Option c. (20,2500) satisfies both the equation.

When there are 20 number of guests, the cost of both moonlight and riverside hall comes out to be 2500.

Moonlight Hall cost

$75 \times 20 + 1000\\\Rightarrow \$2500$

Riverside Hall cost

$50 \times 20 + 1500\\\Rightarrow \$2500$

Answer 3: c. When there are 20 guests attending the price is $2500.

The solution is done in Answer 2.

So,

Answer 1: a. Moonlight: C=75n+1000

Riverside: C=50n+1500

Answer 2: c. The solution coordinates are c. (20, 2500)

Answer 3: c. When there are 20 guests attending the price is $2500.

6 0

2 years ago