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Oliga [24]
3 years ago
5

Five million four thousand three hundred in standard for

Mathematics
2 answers:
3241004551 [841]3 years ago
7 0

Answer:

500,400,300

Step-by-step explanation:

is this correct?

irga5000 [103]3 years ago
6 0

Answer:

Your answer is 5004300

Step-by-step explanation:

Hope this helps u

Crown me as brainliest:)

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Use Conects it’s a better app for math hope this helps
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It takes Joaquin 1/5 hour to hike 1/20 mile. What is Joaquin’s unit rate, in miles per hour?
Yakvenalex [24]
1/5 hour = 1/20
so to get 5/5, or 1 hour
you multiply 1/20*5 to get 5/20
6 0
4 years ago
Read 2 more answers
Write five other iterated integrals that are equal to the given iterated integral. 8 0 x2 0 y f(x, y, z) dz dy dx 0
mash [69]

An iterated integral is the outcome of taking integrals toward a function of more than one variable in such a way that part of the variables is treated as constants for each of the integrals.

From the given parameters, we are to write out five iterations for a triple integral;

\mathbf{\int ^8_0\ \int^{x^2}_{0} \  \int^y_0 \ \  f(x, y, z)  \ dz dy dx }

where;

  • the region is bounded by 0 ≤ z ≤ y, 0 ≤ y ≤ x², 0 ≤ x ≤ 8.

Thus, since x, y, z are functions of at least one variable, we can have the following iterations:

  • \mathbf{\int^{64}_{0} \ \int^{8}_{\sqrt{y}} \ \int^{y}_{0} \ \ f(x,y,z) dz dxdy}

  • \mathbf{\int^{64}_{0} \ \int^{y}_{0} \ \int^{8}_{\sqrt{y}} \ \ f(x,y,z)\ dxdzdy}  

  • \mathbf{\int^{64}_{0} \ \int^{64}_{z} \ \int^{8}_{\sqrt{y}} \ \ f(x,y,z)\ dxdydz}

  • \mathbf{\int^{8}_{0} \ \int^{x^2}_{0} \ \int^{x^2}_{z} \ \ f(x,y,z)\ dydzdx}  

  • \mathbf{\int^{64}_{0} \ \int^{8}_{\sqrt{z}} \ \int^{x^2}_{z} \ \ f(x,y,z)\ dydxdz}  

Learn more about iterated integrals here:

brainly.com/question/7009095

4 0
2 years ago
NAME: A
Lelu [443]

Answer:

4/5

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Find three consecutive odd integers such that eight more than the sum of the first two is equal to eleven less then three times
Sauron [17]
A+b+8 = 11-3c
a+b+3c = 11-8
a+b+3c = 3

a = b-1
c = b+1

b-1+b+3*(b+1) = 3
2b-b+3b+3 = 3
4b = 3-3
4b = 0
b = 0
a = b-1
a = 0-1
a = -1
c = b+1
c = 0+1
c = 1

a = -1, b = 0, c = 1
3 0
4 years ago
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