Y = T+3 (i)
T = H+2 (ii)
Y = 2*H (iiii)
T = H+2 therefore H = T-2
Substitute H=T-2 into (iii)
Y=2*H
Y=2*(T-2)
Y=2T-4
Now substitute that Y into (i)
(i) says Y = T+3
2T-4=T+3
2T-T-4=3
T-4=3
T=3+4
T=7
Then from (i) Y=T+3 = 7+3 =10
Y=10
And from (iii) Y=2*H
If Y = 10, then H = 5
Answer:
10
Step-by-step explanation:
Since y=3x+15
sub 3x+15 for y in other equation
2x+3(3x+15)=1
2x+9x+45=1
minus 45
11x=-44
divide 11
x=-4
sub
y=3x+15
y=3(-4)+15
y=-12+15
y=3
(-4,3)
