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3 years ago

Solve:

\frac{zz}{4} + 5 \geqslant 5.5" alt=" \frac{zz}{4} + 5 \geqslant 5.5" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

allochka39001 [22]3 years ago

7 0

$\bf \cfrac{zz}{4} + 5\geqslant 5.5\implies \stackrel{\textit{subtracting 5 from both sides}}{\cfrac{zz}{4}\geqslant 0.5}\implies \stackrel{\textit{multiplying both sides by 4}}{zz \geqslant 2}$

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Answer:

71° and 71°.

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Step-by-step explanation:

The triangle having two sides equal along with one different side is called an isosceles triangle.

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So, Let us assume the other sides (two equal sides) of the isosceles triangle as x. As the different side is already given in the question.

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We know that,

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So, According to the question :

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${\longrightarrow \it\qquad { \ { { 38 \: }^{ \circ} + x + x = 180{}^{ \circ} }}}$

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${\longrightarrow \it\qquad { \ { { 38 \: }^{ \circ} + 2x = 180{}^{ \circ} }}}$

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${\longrightarrow \it\qquad { \ { 2x = 180{}^{ \circ} - { 38 \: }^{ \circ}}}}$

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${\longrightarrow \it\qquad { \ { 2x = 142{}^{ \circ} }}}$

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${\longrightarrow \it\qquad { \ { x = \dfrac{142{}^{ \circ}}{2} }}}$

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${\longrightarrow \it\qquad { \pmb { x = 71^{ \circ} }}}$

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Therefore,

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