Solve:

\frac{zz}{4} + 5 \geqslant 5.5" alt=" \frac{zz}{4} + 5 \geqslant 5.5" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

allochka39001 [22]3 years ago

7 0

$\bf \cfrac{zz}{4} + 5\geqslant 5.5\implies \stackrel{\textit{subtracting 5 from both sides}}{\cfrac{zz}{4}\geqslant 0.5}\implies \stackrel{\textit{multiplying both sides by 4}}{zz \geqslant 2}$

You might be interested in

An airplane is flying from New York City to Los Angeles. The distance it travels in miles, d, is related to the time in seconds,

yuradex [85]

Answer:

0.15

Step-by-step explanation:

Given the expression that relates the distance and the time with the expression:

d = 0.15t

d is the distance

t is the time

To determine how fast it is flying (Speed), we will need to use the formula

Speed = distance/time

s = d/t

From the given equation we can se that 0.15 = d/t

Comparing this to the general equation, we will see that s = 0.15

Hence the airplane is flying at 0.15

7 0

2 years ago

A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$