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3 years ago

8

Explain how to calculate the surface area of a composite figure in your own words.

2 answers:

AleksAgata [21]3 years ago

8 0

To calculate the <span>surface area of a composite figure you must apply the formulas for calculate the area of each figure that is part of the composite figure and then, you must sum all the areas calculated.

For example, is the composite figure is form by a triangle and rectangle, the surface area of the composite figure will be:

SA= Area of the triangle+ Area of the rectangle= (bh/2)+bh</span>

ivann1987 [24]3 years ago

3 0

Answer:

First separate the composite into component figures. Then find the surface area of each figure. A two-dimensional net can be used to find the surface area. Add the surface areas of the components. Then, subtract or exclude the areas of the figures that are shared.

Step-by-step explanation:

this is the sample answer. hope i helped!

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What figure is comprised of two rays that share a common end point called a vertex?

KIM [24]

This would be called an ANGLE.

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3 years ago

Let f and g be two functions defined as

tia_tia [17]

$a) \: (f \times g)(x) = (2x + 5)( {x}^{2} - 7x + 5) \\ b) \: (f \times g)(4) = (2 \times 4 + 5)( {4}^{2} - 7 \times 4 + 5) = 13( - 7) = - 91$

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3 years ago

Read 2 more answers

HELP SOMEONE PLEASE!!!!! Factor completely 10x2 + 2x − 8. 2

natka813 [3]

Answer:

2(5x - 4)(x + 1)

Step-by-step explanation:

10x^2 + 2x − 8 =

First, factor out the GCF of all terms which is 2.

= 2(5x^2 + x - 4)

5x^2 factors into 5x and x.

= 2(5x )(x )

-4 factors into -4 and 1, -1 and 4, and -2 and 2. Use the set of two factors in the proper positions that will give the middle term.

= 2(5x - 4)(x + 1)

6 0

2 years ago

Read 2 more answers

Х- а<br>x-b<br>If f(x) = b.x-a÷b-a + a.x-b÷a - b<br>Prove that: f (a) + f(b) = f (a + b)

GenaCL600 [577]

Given:

Consider the given function:

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot(x-b)}{a-b}$

To prove:

$f(a)+f(b)=f(a+b)$

Solution:

We have,

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot (x-b)}{a-b}$

Substituting $x=a$ , we get

$f(a)=\dfrac{b\cdot(a-a)}{b-a}+\dfrac{a\cdot (a-b)}{a-b}$

$f(a)=\dfrac{b\cdot 0}{b-a}+\dfrac{a}{1}$

$f(a)=0+a$

$f(a)=a$

Substituting $x=b$ , we get

$f(b)=\dfrac{b\cdot(b-a)}{b-a}+\dfrac{a\cdot (b-b)}{a-b}$

$f(b)=\dfrac{b}{1}+\dfrac{a\cdot 0}{a-b}$

$f(b)=b+0$

$f(b)=b$

Substituting $x=a+b$ , we get

$f(a+b)=\dfrac{b\cdot(a+b-a)}{b-a}+\dfrac{a\cdot (a+b-b)}{a-b}$

$f(a+b)=\dfrac{b\cdot (b)}{b-a}+\dfrac{a\cdot (a)}{-(b-a)}$

$f(a+b)=\dfrac{b^2}{b-a}-\dfrac{a^2}{b-a}$

$f(a+b)=\dfrac{b^2-a^2}{b-a}$

Using the algebraic formula, we get

$f(a+b)=\dfrac{(b-a)(b+a)}{b-a}$ $[\because b^2-a^2=(b-a)(b+a)]$

$f(a+b)=b+a$

$f(a+b)=a+b$ [Commutative property of addition]

Now,

$LHS=f(a)+f(b)$

$LHS=a+b$

$LHS=f(a+b)$

$LHS=RHS$

Hence proved.

5 0

2 years ago

Help!!!! how many will 12 shirts cost!?

Basile [38]

Answer:

240

Step-by-step explanation:

60/3=20

1 shirt costs $20 sooo...

20x12=240

$240

can i get branilest for first answer

3 0

3 years ago