Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
Answer:
x = 5 or x = 2 or x = 0 or x = -3 thus 0 is the smallest root
Step-by-step explanation:
Solve for x:
x (x - 5) (x - 2) (x + 3) = 0
Split into four equations:
x - 5 = 0 or x - 2 = 0 or x = 0 or x + 3 = 0
Add 5 to both sides:
x = 5 or x - 2 = 0 or x = 0 or x + 3 = 0
Add 2 to both sides:
x = 5 or x = 2 or x = 0 or x + 3 = 0
Subtract 3 from both sides:
Answer: x = 5 or x = 2 or x = 0 or x = -3
Answer:
<h2>
<em><u>60</u></em></h2>
Step-by-step explanation:
tiny stuffed zebras(tsz)= $3
giant stuffed zebras(gsz)=$14
total sold=$208
208÷3=69.3recurring so that's incorrect as you cannot sell .3 of a zebra so keep going until you find the next whole number. (trial and error)
207÷3=69 but it cant be this as it is not the whole money made
208-14=194
194÷3=64.6recurring (cannot be this)
194-14=180
180÷3= 60 = answer as 60 tsz is $180 and add that to 2 gsz and that totals to 208 which is the total
Answer:(-22)
Step-by-step explanation:
What is the value of h (-2) when h (3) = 32 +1?
hx3=33
33 divided by 3
which means h=11
that makes 11(-2)
=(-22)