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dlinn [17]
4 years ago
7

]. six pears and three apples cost $3.90. two pears and five apples cost $3.30. how much does one pear cost

Mathematics
1 answer:
Ilya [14]4 years ago
6 0
Write the equation of the cost
p stands for the cost per pear, a stands for the cost per apple
6p + 3a = 3.9
2p + 5a = 3.3

Solve the equation system
To solve the equation system, we work on eliminating variable p so we will find the number of a. To eliminate, we have to change the coefficient of p to the same number (i will change it to coefficient 6)
6p + 3a = 3.9 (multiply 1)
2p + 5a = 3.3 (multiply 3)
---------------------------------
6p + 3a = 3.9
6p + 15a = 9.9
-------------------- - (substract)
      -12a = -6
           a = -6/-12
           a = 0.5

To find the cost per pear, subtitute the number of a to one of the equation
2p + 5a = 3.3
2p + 5(0.5) = 3.3
2p + 2.5 = 3.3
2p = 3.3 - 2.5
2p = 0.8
p = 0.4

The cost of one pear is $0.4
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One positive integer is 3 less than twice another. the sum of their squares is 233. find the integers.
lana66690 [7]
Let the two integers be x and y
x-3= 2y
x=2y+3______(1)

x²+y²= 233_____(2)
sub eqn (1) into (2)
{2y+3}²+y²=233
4y² + 12y +9 +y²=233
5y²+12y+9-233=0
5y²+12y-224=0
y= -8 or 5.6
recall they are positive integers so y=5.6
now sub y=5.6 into eqn (1)
x=2(5.6)+3 = 11.2+3=14.2

the two integers are 14.2 and 5.6
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4 years ago
Two vertical buildings 57 meters apart are 158 meters and 237 meters high. Find the angle of elevation from the top of the short
miskamm [114]

Given :

Two vertical buildings 57 meters apart are 158 meters and 237 meters high.

To Find :

The angle of elevation from the top of the shorter building to the top of the taller building.

Solution :

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Distance between these building , d = 57 m.

Now,

tan\ \theta = \dfrac{h}{d}\\\\tan\ \theta = \dfrac{79}{57}\\\\tan\ \theta = 1.386\\\\\theta = tan ^{-1} 1.386\\\\\theta = 54.19^{\circ}

Therefore, the angle of elevation from the top of the shorter building to the top of the taller building is 54.19°.

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Answer: -2

Step-by-step explanation:

When x is 0, y is -2.

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IrinaK [193]

Answer:

The horizontal distance from the plane to SCCA is 32,708.5\ ft

Step-by-step explanation:

Let

x-----> the horizontal distance from the plane to SCCA

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see the attached figure to better understand the problem

tan(17\°)=\frac{10,000}{x}

x=\frac{10,000}{tan(17\°)}

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