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3 years ago

7

]. six pears and three apples cost $3.90. two pears and five apples cost $3.30. how much does one pear cost

1 answer:

Ilya [14]3 years ago

6 0

Write the equation of the cost
p stands for the cost per pear, a stands for the cost per apple
6p + 3a = 3.9
2p + 5a = 3.3

Solve the equation system
To solve the equation system, we work on eliminating variable p so we will find the number of a. To eliminate, we have to change the coefficient of p to the same number (i will change it to coefficient 6)
6p + 3a = 3.9 (multiply 1)
2p + 5a = 3.3 (multiply 3)
---------------------------------
6p + 3a = 3.9
6p + 15a = 9.9
-------------------- - (substract)
-12a = -6
a = -6/-12
a = 0.5

To find the cost per pear, subtitute the number of a to one of the equation
2p + 5a = 3.3
2p + 5(0.5) = 3.3
2p + 2.5 = 3.3
2p = 3.3 - 2.5
2p = 0.8
p = 0.4

The cost of one pear is $0.4

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The capital formation of the investment function over a given period is the

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(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

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