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love history [14]
3 years ago
14

Determine the equation of the inverse of y= 2^3x-1

Mathematics
1 answer:
MariettaO [177]3 years ago
6 0

Answer:

f^-1(x)= 1/3+In(x)/3 In(2)

Step-by-step explanation:

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3 years ago
A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute
Katyanochek1 [597]

Answer:

Step-by-step explanation:

Given that:

sample size n = 36

standard deviation = 10.1

level of significance ∝ = 0.10

The null hypothesis and the alternative hypothesis can be computed as follows:

H_0 : \sigma = 10

H_1 : \sigma \neq 10

The test statistics can be computed as follows:

X^2 = \dfrac{(n -1)s^2 }{\sigma ^2}

X^2 = \dfrac{(36 -1)10.1^2 }{10^2}

X^2 = \dfrac{(35)102.01 }{100}

X^2 = \dfrac{3570.35 }{100}

X^2 =35.704

degree of freedom = n - 1 = 36 - 1 = 35

Since this test is two tailed .

The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)

P - value = 2 × 0.435163515

P - value = 0.8703      ( to four decimal places)

Decision Rule : To reject the null hypothesis if  P - value is less than the 0.10

Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.

3 0
3 years ago
Hello i need some help
Natalija [7]

Answer:

y = 2x - 1

Step-by-step explanation:

(3, 5) (5, 9)

slope = (9-5)/(5-3) = 4/2 = 2

y = mx + b

5 = 2(3) + b

-1 = b

y = 2x -1

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3 years ago
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The first number in a pattern is 8 .Each following number is found by subtracting 9 from the previous number. What is the fifth
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Answer:

poop sock

Step-by-step explanation:

poop sock

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3 years ago
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Divide 150 into 3 parts in the proportion of 4, 6 and 2 1/2 respectively<br><br>​
Feliz [49]

Answer:

Hope this helps!!

Step-by-step explanation:

4 = 48

6 = 72

2 \frac{1}{2} = 30

PLZZ MARK BRAINLIEST

5 0
2 years ago
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