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3 years ago

What is the difference 13-5=

Mathematics

2 answers:

shepuryov [24]3 years ago

5 0

The difference between the two is 8

pentagon [3]3 years ago

4 0

The correct answer is 8.
Hope this helped!

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translate the words into a algebraic expression. "twenty-seven more than a number squared" "one less than three times a number"

Stella [2.4K]

Answer:

$n^2+27$ and $3n-1$

Step-by-step explanation:

n is a number.

a number squared is $n^2$

27 more than a number squared is $n^2+27$

n is a number.

three times a number is 3 times n, or $3n$

one less than that is $3n-1$

Hope this answer helped! :)

3 0

3 years ago

How do you read this expression 8(8x+7) and 8(3x)+8(7)

Misha Larkins [42]

Answer:

64x+56 & 24x+56

Step-by-step explanation:

I hope this is what you mean because this is not an equation as it is not set equal to anything.

Both problems solved by distributive property -

8*8x + (8*7) = 64x+56

8*3x + (8*7) = 24x+56

4 0

3 years ago

Evaluate -5 - 15 + 4 + 15

dexar [7]

Answer:

Step-by-step explanation:

-5+-15= -20

4+15= 19

-20+19

-1

7 0

3 years ago

Read 2 more answers

Find the limit, if it exists, or type dne if it does not exist.

Phantasy [73]

$\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}$

Suppose we choose a path along the $x$ -axis, so that $y=0$ :

$\displaystyle\lim_{x\to0}\frac{x^2}{x^2}=\lim_{x\to0}1=1$

On the other hand, let's consider an arbitrary line through the origin, $y=kx$ :

$\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}$

The value of the limit then depends on $k$ , which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.

8 0

3 years ago

A. IfA= {a, b} and B = {p, q, r}, find A x B and B x A using tree diagram.

Katarina [22]

Answer:

Step-by-step explanation:

8 0

3 years ago