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nordsb [41]
3 years ago
7

What is three numbers that's greater than 20 and have 9 as a factor

Mathematics
2 answers:
TEA [102]3 years ago
7 0
27, 36, and 45 are all greater than 20 and have 9 as a factor
ASHA 777 [7]3 years ago
4 0
The answer to your question is 27, 36, 45
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130% of the sum of 7 and a number n is equal to 91.
dybincka [34]
130\%(7+n)=91 \\
1.3(7+n)=91 \\
7+n=\frac{91}{1.3} \\
7+n=70 \\
n=70-7 \\
n=63
4 0
3 years ago
Read 2 more answers
Tom received a $70 gift card for a cafe. He used it to buy some coffee that cost $7.73 per pound. After buying the coffee, he ha
mart [117]

Answer: He bought 6 pounds of coffee.

Step-by-step explanation:

Money he have = 70

money he used to buy = 70.00 - 23.62 = 46.38

so

7.73 dollar = 1 pound

1 dollar = 1/(7.73) = 100/773 pound

46.38 dollar = (100/773) * 46.38 = 6 pound

5 0
3 years ago
4g + 3(-3 + 4g) = 1-g. Solve the equation. Can someone help me ASAP. I'm confused
Olegator [25]
4g+3(-3+4g)=1-g
Distribute the 3(-3+4g)
4g-9+12g=1-g
Add 4g and 12g
16g-9=1-1g
Add 1g and 16g (variables always have an invisible 1 in front)
17g-9=1
Add 9 and 1
17g=10
Divide both sides by 17 and the answer is g=10/17
5 0
3 years ago
Let ​f(x)equals=33xminus−​1, ​h(x)equals=startfraction 7 over x plus 5 endfraction 7 x+5 . find ​(hcircle◦​f)(66​).
Ronch [10]
\bf \begin{cases}
f(x)=3x-1\\
h(x)=\cfrac{7}{x+5}\\\\
(h\circ f)(x)=h(~~f(x)~~)
\end{cases}
\\\\\\
f(66)=3(66)-1\implies \boxed{f(66)=197}
\\\\\\
\stackrel{h(~~f(x)~~)}{h(~~f(66)~~)}\implies \stackrel{h(~~f(66)~~)}{h\left(~~\boxed{197}~~ \right)}=\cfrac{7}{\boxed{197}+5}\implies h\left(~~\boxed{197}~~ \right)=\cfrac{7}{202}
7 0
3 years ago
Anyone know what the answer is
vagabundo [1.1K]
Well for 1.4 will be 1, 2.2 will be 2, 0.7 will be 1, 3.9 will be 4, and 1.8 is 2
7 0
3 years ago
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