Answer:
\large \boxed{\textbf{Bowl = 300 g; cup = 200 g}}
Step-by-step explanation:
Let b = the mass of a bowl
and c = the mass of a cup
We have two conditions:

Calculations:

Check:

OK.
Please send a picture of the figure
You'd get a total 24 cups, 3/5=9/15. 9+15=24
Answer:
a) -3 gallons per hour
b) y = -3x +14
Step-by-step explanation:
Rate of change is computed by dividing the amount of change by the interval over which it occurred.
<h3>a)</h3>
Here the amount of gas decreased from 14 to 2 gallons, so a decrease of 14-2 = 12 gallons. That occurred over a 4-hour period, so the rate of change is (-12 gallons)/(4 hours) = -3 gallons/hour.
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<h3>b)</h3>
The initial amount was 14 gallons, so the equation for the line describing remaining gas will be ...
y = -3x +14 . . . . gas in the tank after x hours